Using the expected value, it is found that you should charge $4 to have a fair game.
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- A probability is the <u>number of desired outcomes divided by the number of total outcomes</u>.
- The expected value is the <u>sum of each outcome multiplied by it's respective probability</u>.
- When you roll two dice, there are possible outcomes.
- We suppose a cost of x.
- In 6 of them, the sum is 7: (1,6), (2,5), (3,4), (4,3), (5,2) and (6,1).
- Thus, probability of earning a profit of 12 - x.
- 2 of them have sums of 2 or 12, which are (1,1) and (6,6).
- Then, probability of earning a profit of 36 - x.
- If the outcome is any of the remaining 28, the player loses, thus probability of losing x.
- The game is fair if the <u>expected value is 0</u>, then:
A value of $4 should be charged.
A similar problem is given at brainly.com/question/24855677
Our two ratios are 4/21 and 3/14
we have to add them together
to do this, they have to have the same denominator
lets give them the denominator of 42
9/42 + 8/42 = 17/42
17 out of every 42 cards is faulty
So you only have 3 sides so the perimeter will be length+2width instead of 2length+2 width
l+2w= perimeter
you know the length of the longest side is 15
15+2w = perimeter
and you also know that he is using 31 feet of fencing
15+2w = 31
2w = 16
w=8
Answer:
215 divided by 23 is 9.34
27 / 2.25 =
1 / x =
Divide 2.25 by 27 to get
.08 dollars per ounce