Answer:
y + 4x - 6 = 0
Step-by-step explanation:
Rearranging the given equation:-
4y = x + 24
y = 1/4 x + 6
This has a y intercept of (0, 6) and a slope of 1/4.
Thus, the other line has a slope of -4 and passes through the point (0,6) also.
Using the Point-slope form of a straight line:-
y - y1 = m(x - x1)
y - 6 = -4(x - 0)
y + 4x - 6 = 0 is the required equation
Answer:
The width of the field is 4x + 20 / x² -2x -3 yards
Step-by-step explanation:
The area of a rectangular field is given by the following formula:
area = length*width
In this case we want to find the width of this field, therefore if we isolate the width in the expression above we will have a suitable expression:
width*length = area
width = area / length
So applying the data from the problem, we have:
width = [(2x + 6)/(x + 1)] / [(x² - 9)/(2x + 10)]
width = [(2x + 6)/(x + 1)]*[(2x + 10)/(x² - 9)]
width = 2(x + 3)*(2x + 10) / (x+1)*(x - 3)*(x + 3)
width = 2*(2x + 10) / (x + 1)*(x - 3)
width = 4x + 20 / x² -2x -3
For the equation F(x) = ax² + bx + c we have:
- maximum value if a<0
- minimum value if a>0
F(x) = -3x² + 18x + 3 ⇒ a = -3, b = 18
a < 0 ⇒ the function has a maximum value
Quadratic function has the maximum value (or minimum) at vertex of its parabola.
The maximum value is k at x=h where: 
and k = F(h)
Therefore:
<h3>
The function has a maximum value of 30 at x = 3</h3>
“42.3” I wish I got easy questions like you do
