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Finger [1]
1 year ago
6

The bowling scores for six people are: 22,114,115,120,122,125What is the most appropriate measure of center? A.the median B.the

range C.the standard deviation D.the mean
Mathematics
1 answer:
makkiz [27]1 year ago
4 0

To find the correct answer we have to find the median, the mean, the range

To find the median arrange the scores from smallest to greatest

22, 114, 115, 120, 122, 125

The median is the average of the 2 middle scores

Since the middle scores are 115, and 120, then

The median is

\begin{gathered} \text{Med}\mathrm{}=\frac{115+120}{2} \\ \text{Med}\mathrm{}=117.5 \end{gathered}

The mean is the sum of the scores divided by the number of scores

\begin{gathered} \text{Mean}=\frac{22+114+115+120+122+125}{6} \\ \text{Mean}=103 \end{gathered}

Because of the lower score (22) the mean, not an appropriate measure of center

The range is the difference between the greatest and the smallest score

Since the greatest score is 125 and the smallest score is 22, then

\begin{gathered} \text{Range}=125-22 \\ \text{Range}=103 \end{gathered}

It is the same with the mean, then it is also not an appropriate measure of center

The standard deviation is for a sample of scores, then it is not the answer

Then the most appropriate measure of center is the median

The answer is A

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An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 37 type K batteries and a sample of 58
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Answer:

Step-by-step explanation:

Hello!

You want to test two samples of batteries to see is the mean voltage of these battery types are different.

<u>Sample 1 </u>(type K)

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standard deviation S₁= 0.225

<u>Sample 2 </u>(Type Q)

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1. The test hypothesis are:

H₀: μ₁ = μ₂

H₁: μ₁ ≠ μ₂

2. I'll apply the Central Limit Theorem and approximate the distribution of the sample means to normal so that I can use an approximate Z statistic for this test.

Z:<u> (x₁[bar] - x₂[bar]) - (μ₁ - μ₂)</u> ≈ N(0;1)

        √ (S₁²/n₁) + (S₂²/n₂)

Z_{H0}= (8.54 - 8.69) / [√ (0.225²/37) + (0.725²/58)]

Z_{H0}= -1.468 ≅ -1.47

3. This is a two tailed test, so you'll have two critical values

Z_{\alpha/2} = Z_{0.025} = - 1.96

Z_{1 - \alpha/2} = Z_{0.975} = 1.96

You'll reject the null hypothesis if Z_{H0} ≤ -1.96 or if Z_{H0} ≥ 1.96

You'll not reject the null hypothesis if -1.96 < Z_{H0} < 1.96

4.

Since the value Z_{H0} = -1.47 is in the acceptance region, the decision is to not reject the null hypothesis.

I hope it helps!

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Se tienen 224 plumas de color negro y 420 de color rojo. Se quiere ponerlas en cajas iguales, de tal manera que cada caja tenga
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Answer:

La cantidad de plumas que se deben poner en cada caja para que se utilice el menor número posible de cajas es 28.

Requieres 8 cajas con plumas de color negro y 15 cajas con plumas de color rojo, necesitando 23 cajas en total.

Step-by-step explanation:

El divisor común  es un número que es divisor a la vez de dos o más números, es decir, es un divisor común a esos números.

Por lo que se denomina máximo común divisor o M.C.D al mayor número que divide exactamente a dos o más números a la vez. En otras palabras, el Máximo Común Divisor es el mayor de los divisores comunes de varios números.

Para calcular el M.C.D, se descompone cada uno de ellos en factores primos. El M.C.D. es el resultado de multiplicar los factores que se repitan en todas las descomposiciones, afectados por el menor exponente.

En este caso, los números 224 y 420 se descomponen en:

224= 2⁵*7

420= 2²*3*5*7

Entonces, el M.C.D entre 224 y 420 es calculado como 2²*7, que da como resultado 28. Esto indica que <u><em>la cantidad de plumas que se deben poner en cada caja para que se utilice el menor número posible de cajas es 28. </em></u>

Para el calculo de cantidad de cajas que se necesitan, primero es necesario saber cuántas cajas de cada color de plumas se necesitan. Para eso, debes dividir la cantidad de plumas que tienes por la cantidad de cajas por las que debes repartirlo:

224 plumas negras÷ 28= 8

420 plumas rojas÷ 28= 15

Por lo que <u><em>requieres 8 cajas con plumas de color negro y 15 cajas con plumas de color rojo, necesitando 23 (8+15) cajas en total.</em></u>

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