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Murljashka [212]
1 year ago
14

T/F static development is the process of constructing the programs and code modules that serve as the building blocks of the inf

ormation system.
Computers and Technology
1 answer:
Triss [41]1 year ago
3 0

Application development is the process of creating the programs and code modules that act as the foundation of the information system.

What Is Application Development?

The process of designing, creating, and implementing software applications is referred to as application development, also referred to as app development. Either a single independent developer or sizable organizations with large teams working on projects can carry it out. Application development outlines the steps involved in creating an application and typically adheres to a set methodology.

The process of developing an application is influenced by numerous factors. You must take into account the project's size, the requirements' level of specificity, the customer's willingness to request changes, the size and experience of the development team, as well as the project's deadline.

The software development life-cycle and application development are closely related processes (SDLC).

To know more about SDLC, check out:

brainly.com/question/15696694

#SPJ1

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You want to find information about Paris, France in the last five years, written in English. What is the best way to search for
KonstantinChe [14]
I say It could be B
8 0
3 years ago
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Business customers pay $0.006 per gallon for the first 8000 gallons. If the usage is more than 8000 gallons, the rate will be $0
trasher [3.6K]

Answer:

#include <bits/stdc++.h>

using namespace std;

int main()

{

   // variables

   char cust_t;

   int no_gallon;

   double cost=0;

   cout<<"Enter the type of customer(B for business or R for residential):";

   // read the type of customer

   cin>>cust_t;

   // if type is business

   if(cust_t=='b'||cust_t=='B')

   {

       cout<<"please enter the number of gallons:";

       // read the number of gallons

       cin>>no_gallon;

       // if number of gallons are less or equal to 8000

       if(no_gallon<=8000)

       {

           // calculate cost

           cost=no_gallon*0.006;

           cout<<"total cost is: $"<<cost<<endl;

       }

       else

       {

           // if number of gallons is greater than 8000

           // calculate cost

           cost=(8000*0.006)+((no_gallon-8000)*0.008);

           cout<<"total cost is: $"<<cost<<endl;

           

       }

       

   }

   

   // if customer type is residential

   else if(cust_t=='r'||cust_t=='R')

        {

           

       cout<<"please enter the number of gallons:";

       // read the number of gallons

       cin>>no_gallon;

       // if number of gallons are less or equal to 8000

       if(no_gallon<=8000)

       {

           // calculate cost

           cost=no_gallon*0.007;

           cout<<"total cost is: $"<<cost<<endl;

       }

       else

       {// if number of gallons is greater than 8000

       // calculate cost

           cost=(8000*0.005)+((no_gallon-8000)*0.007);

           cout<<"total cost is: $"<<cost<<endl;      

       }        

   }

return 0;

}

Explanation:

Ask user to enter the type of customer and assign it to variable "cust_t". If the customer type is business then read the number of gallons from user and assign it to variable "no_gallon". Then calculate cost of gallons, if  gallons are less or equal to 800 then multiply it with 0.006.And if gallons are greater than 8000, cost for  first 8000 will be multiply by 0.006 and  for rest gallons multiply with 0.008.Similarly if customer type is residential then for first 8000 gallons cost will be multiply by 0.005 and for rest it will  multiply by 0.007. Then print the cost.

Output:

Enter the type of customer(B for business or R for residential):b                                                                                            

please enter the number of gallons:9000                                                                                                                      

total cost is: $56  

4 0
3 years ago
How does limiting a company's scope benefit the company? A. It encourages the company to use division of labor. B. It makes it e
Luda [366]

Answer

It makes it easier to produce a high quality product.

Explanation

Project scope is the part of project planning that involves determining and documenting a list of specific project goals, deliverable, tasks, costs and deadlines. in Project management it  involves the planning and organization of a company's resources to complete a specific task, event, or action and is usually a one-time event. It is an activity that is engaged in for the primary purpose of making a profit. These activities includes things like  production, operations, marketing, and administration

6 0
3 years ago
Read 2 more answers
Write a class called Course that represents a course taken at a school. Represent each student using the modified Student class
Vinvika [58]

Answer:

The code is given below with its appropriate output

Explanation:

//Student.java

import java.io.BufferedReader;

import java.io.FileReader;

import java.io.IOException;

import java.util.Scanner;

public class Student {

public String firstName;

public String lastName;

public float[] marks;

Scanner scanner = new Scanner(System.in);

public Student(String firstName, String lastName) {

this.firstName = firstName;

this.lastName = lastName;

}

public void getdetail() {

System.out.println("enter only five marks");

marks = new float[5];

int count = 0;

for (int i = 0; i < 5; i++) {

float mark = 0;

++count;

if (count <= 5) {

System.out.println("enter score " + count);

mark = scanner.nextFloat();

if (mark >= 0.0 && mark <= 100.0)

marks[i] = mark;

else {

System.out.println("you entered mark is invalid");

marks[i] = 0;

}

} else

System.out.println(" maximum is five only");

}

}

public void tostring() {

System.out.println("firstname :" + "\t" + firstName + "\t" + "lastname :"

+ "\t" + lastName + "\n" + "the marks are");

int count = 0;

for (float mark : marks) {

count++;

System.out.println("the mark of " + count + " is " + mark);

}

}

public void Averagecal() {

float sum = 0.0f;

for (float mark : marks) {

sum = sum + mark;

}

float avg = sum / 5;

System.out.println("average of a student is " + avg);

}

}

//Course.java

import java.io.*;

import java.io.BufferedReader;

import java.io.FileReader;

import java.io.IOException;

import java.util.Scanner;

public class Course {

public String courseName;

public int number;

Student[] students;

Scanner scanner = new Scanner(System.in);

public Course(String courseName) {

this.courseName = courseName;

}

public void addStudents() {

System.out

.println("how many no of students you want to add for this particular course");

int count = scanner.nextInt();

students = new Student[count];

for (int i = 0; i < count; i++) {

System.out.println("enter the first name");

String fname = scanner.next();

System.out.println("enter the last name");

String lname = scanner.next();

Student s = new Student(fname, lname);

s.getdetail();

s.tostring();

s.Averagecal();

students[i] = s;

}

}

public void roll() {

int count = 0;

for (Student stud : students) {

count++;

}

System.out.println("the no of students in this " + courseName

+ " course is " + count);

}

}

//Driver.java

import java.io.BufferedReader;

import java.io.FileReader;

import java.io.IOException;

import java.util.Scanner;

public class Driver {

public static void main(String[] args) {

Course course = new Course("java");

course.addStudents();

course.roll();

}

}

<u>output: </u>

C:\Users\Daniel\Desktop\New folder>javac Student.java

C:\Users\Danie;\Desktop\New folder>javac Course.java

C:\Users\Daniel\Desktop\New folder>javac Driver.java

C:\Users\Daniel\Desktop\New folder>java Driver

how many no of students you want to add for this particular course ?

1

enter the first name

john

enter the last name

rich

enter only five marks

enter score 1

89

enter score 2

91

enter score 3

85

enter score 4

78

enter score 5

96

firstname : john lastname : rich

the marks are

the mark of 1 is 89.0

the mark of 2 is 91.0

the mark of 3 is 85.0

the mark of 4 is 78.0

the mark of 5 is 96.0

average of a student is 87.8

the no of students in this java course is 1

C:\Users\Ravi\Desktop\New folder>

3 0
3 years ago
You try to enter your name into a cell that accepts a numeric value. What error would you receive? A. #NAME B. #VALUE C. #REF D.
UNO [17]

Answer:

<h2>Option B: #VALUE</h2>

is the correct answer.

Explanation:

<h3>Reasons of #VALUE error:</h3>
  • When cells are not given the expected type of value.
  • If cells are left blank unnoticeable or for giving a null value.
  • For entering dates and other numerical data in text form.
<h3>Correcting and fixing #VALUE error:</h3>

This type of error can only be fixed by finding the cell in which there is wrong data entered and correct it.

Fixing the #VALUE error is tricky as some functions automatically ignore the data that is invalid.

<h3>EXAMPLE:</h3>
  • Suppose a cell contains the value as cost of the object and in order to make it 0, NA is inserted into the cell.
  • While making total of all the costs, that particular cell might cause #VALUE error.
  • Following image attach will help you clear the concept.

I hope it will help you!

4 0
3 years ago
Read 2 more answers
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