Step-by-step explanation:
d = z - 9
d = 10 - 9 ----> substitute
d = 1
Answer:
I don't think I can remember every skill I was taught through the years but in Kindergarten we used Number Sense so we could understand the meaning of more and less also there's estimation and PEMDAS. I've also learned how to round up so that the solution is at least around those numbers if the skill is to be applied.
hope that helps
Step-by-step explanation:
Answer:
1.85
Step-by-step explanation:
20.2-18.35=1.85
9514 1404 393
Answer:
-2
Step-by-step explanation:
-8^(1/3) = -(2^3)^(1/3) = -(2^(3/3)) = -2
Answer:
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Step-by-step explanation:
We have been given a function
. We are asked to find the zeros of our given function.
To find the zeros of our given function, we will equate our given function by 0 as shown below:

Now, we will factor our equation. We can see that all terms of our equation a common factor that is
.
Upon factoring out
, we will get:

Now, we will split the middle term of our equation into parts, whose sum is
and whose product is
. We know such two numbers are
.




Now, we will use zero product property to find the zeros of our given function.




Therefore, the zeros of our given function are
.