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olga_2 [115]
3 years ago
11

Megan's family had cakes on two days. The first day, they had 2 3/4 cakes left. The second day, they had 1 1/4 cakes left. How m

any cakes were left in all?
Mathematics
1 answer:
vlabodo [156]3 years ago
8 0

Answer: 4 cakes left in all.


Step-by-step explanation:

Given: Cakes left on first day= 2\frac{3}{4}=\frac{11}{4}

Cakes left on second day =1\frac{1}{4}=\frac{5}{4}

The number of cakes left in all=\frac{11}{4}+\frac{5}{4}

⇒The number of cakes left in all=\frac{11+5}{4}=\frac{16}{4}

Therefore, The number of cakes left in all=4

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\boxed{\pink{\sf The \ number \ of \ cubes \ that \ can \ be \ fitted \ is 60 .}}

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