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Anvisha [2.4K]
1 year ago
7

Simplify and write the trig expression in terms of sin and cos

Mathematics
1 answer:
dsp731 year ago
6 0

We have:

cot(-x)cos(-x)+sin(-x)=-\frac{1}{f(x)}

Then we use trigonometric identities to change the negative sign of the trigonometric functions, so:

-sin(x)-cot(x)cos(x)=-\frac{1}{f(x)}

We clear f(x):

f(x)=\frac{1}{sin(x)+cot(x)cos(x)}=\frac{1}{sin(x)+\frac{cos(x)}{sin(x)}cos(x)}=\frac{1}{sin(x)+\frac{cos^2(x)}{sin(x)}}

we simply what we can:

f(x)=\frac{1}{\frac{sin^2(x)+cos^2(x)}{sin(x)}}=sin(x)

Thus, the correct answer is;

f(x)=sin(x)

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Answer:

This is very easy. First find the volume of the cube, and then add it to the volume of the hemisphere to find the total volume.

The volume of the cube is length x width x height: 8 x 8 x 12 = 768 cm

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3 years ago
Please help me with 7 and 9 I’m really confused and I really need help!!
Margarita [4]

Answer:

  7) K'(1, 1), N'(4, 0), Q'(4, 4)

  9) F'(4, 2), W'(4, 5), K'(3, 2)

Step-by-step explanation:

When you are not sure about reflections and rotations, it can be useful to actually draw a graph. The line of reflection is the perpendicular bisector of the segment connecting a point with its image. That is, the image is the same distance from the line on the other side. A point that is <em>on</em> the line of reflection is "invariant," it doesn't move.

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7) Reflecting across the x-axis changes the sign of the y-coordinate. That is all. Any point on the x-axis (y=0) is unchanged. The transformation is ...

  (x, y) ⇒ (x, -y)

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9) Reflecting across a vertical line changes the x-coordinate. The new value of x will be ...

  x' = 6 - x

The "6" is double the x-coordinate of the vertical line. The transformation is ...

  (x, y) ⇒ (6-x, y)

_____

<em>Derivation of the formula for reflection on x=3</em>

In general if M is the midpoint of a point (A) and its reflection (A'), then we have ...

  M = (A +A')/2

  2M = A + A'

  2M -A = A'

When a point is reflected across a vertical line, all of the y-coordinate values remain unchanged. So, for A=(x, y) and M=(3, y), we have ...

  A' = 2(3, y) -(x, y) = (6-x, 2y-y)

  A' = (6 -x, y)

So, the reflection transformation across the line x = 3 is ...

  (x, y) ⇒ (6-x, y)

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Answer:

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Step-by-step explanation:

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Please help.<br> Algebra.
iogann1982 [59]
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3 years ago
(x,5), (-3,6); slope = -1
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