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10 months ago

Determine which set of side measurements could be used to form a right triangle.

1 answer:

3 0

The set of side measurements that could be used to form a right triangle is 3, 4 and 5 option (D) is correct.

What is a right-angle triangle?

It is a triangle in which one of the angles is 90 degrees and the other two are sharp angles. The sides of a right-angled triangle are known as the hypotenuse, perpendicular, and base.

It is given that:

The side length of the triangle is shown in the option:

As we know,

Pythagoras' theorem is the square of the hypotenuse in a right-angled triangle is equal to the sum of the squares of the other two sides.

Using Pythagoras' theorem:

From option(D):

3, 4 and 5

(3)² + (4)² = 5²

9 + 16 = 25 (True)

Thus, the set of side measurements that could be used to form a right triangle is 3, 4 and 5 option (D) is correct.

Learn more about the right-angle triangle here:

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Brian is 2 years older than Malachy. Caroline is 8 years younger than Malachy. If the total of their ages is 66, how old is the

SVETLANKA909090 [29]

Answer:

The eldest of them is Brian and he is 24 + 2 = 26 years old.

Step-by-step explanation:

Let

Malachy age = a

Brian age = a + 2

Caroline age = a - 8

Total of their age = a + (a + 2) + (a - 8)

66 = a + (a + 2) + (a - 8)

collect like terms

66 = a + a + 2 + a - 8

66 = a + a + a - 6

3a = 66 + 6

3a = 72

divide both sides by 3

a = 72/3

a = 24

Malachy age is 24 . Caroline is 24 - 8 = 16 years old.

The eldest of them is Brian and he is 24 + 2 = 26 years old.

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3 years ago

An above swimming pool is leaking after 1/2 hour the pool has leaked 7/8 of a gallon of water

Luden [163]

The answer to your question are 1.75

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3 years ago

Verify that the roots of 5x²- 6x -2 = 0 are <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%20%2B%20%5Csqrt%7B19%7D%20%7D%7B5%7D%2

Mice21 [21]

Answer:

Proof below.

Step-by-step explanation:

Quadratic Formula

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Given quadratic equation:

$5x^2-6x-2=0$

Define the variables:

a = 5
b = -6
c = -2

Substitute the defined variables into the quadratic formula and solve for x:

$\implies x=\dfrac{-(-6) \pm \sqrt{(-6)^2-4(5)(-2)}}{2(5)}$

$\implies x=\dfrac{6 \pm \sqrt{36+40}}{10}$

$\implies x=\dfrac{6 \pm \sqrt{76}}{10}$

$\implies x=\dfrac{6 \pm \sqrt{4 \cdot 19}}{10}$

$\implies x=\dfrac{6 \pm \sqrt{4}\sqrt{19}}{10}$

$\implies x=\dfrac{6 \pm2\sqrt{19}}{10}$

$\implies x=\dfrac{3 \pm \sqrt{19}}{5}$

Therefore, the exact solutions to the given quadratic equation are:

$x=\dfrac{3 + \sqrt{19}}{5} \:\textsf{ and }\:x=\dfrac{3 - \sqrt{19}}{5}$

Learn more about the quadratic formula here:

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1 year ago

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2/3 divided by 7/12 PLSLSLSLSLSLLSLSL

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Answer:

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Step-by-step explanation:

Find the reciprocal of the divisor

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