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2 years ago

Answer I will mark your brainlist

Mathematics

1 answer:

yan [13]2 years ago

3 0

Answer:

Mark C.

Step-by-step explanation:

If there are 27 students in both classes, it's logicial to multiply both classes by two to get the total students.

Since the <em>S</em> stands for the students absent, that should come after the brackets.

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Please help me with this please answer this correctly

sergij07 [2.7K]

30 and 13

x-y=17 and x+y=43

x=17+y and x=43-y, so 17+y=43-y

so y=13

43-13=30, so x=30 and y=13

8 0

2 years ago

Which of these always has congruent diagonals?

docker41 [41]

Answer:

rectangle

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

5.346 - 2.289= 3.057 <br><br> SHOW WORK!!!! <br><br> WILL GIVE BRAINLIEST PLEASE

Ilya [14]

brainly.com/question/13983892

5 0

2 years ago

Use the standard norml distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justif

dalvyx [7]

Answer:

E) we will use t- distribution because is un-known,n<30

the confidence interval is (0.0338,0.0392)

Step-by-step explanation:

Given sample size is n = 23<30 mortgage institutions

The mean interest rate 'x' = 0.0365

The standard deviation 'S' = 0.0046

the degree of freedom = n-1 = 23-1=22

99% of confidence intervals $t_{0.01} =2.82$ (from tabulated value).

$The mean value = 0.0365$

$x±t_{0.01} \frac{S}{\sqrt{n-1} }$

$0.0365±2.82 \frac{0.0046}{\sqrt{23-1} }$

$0.0365±2.82 \frac{0.0046}{\sqrt{22} }$

$0.0365±2.82 \frac{0.0046}{4.690 }$

using calculator

$0.0365±0.00276$

Confidence interval is

$(0.0365-0.00276,0.0365+0.00276)$

$(0.0338,0.0392)$

the mean value is lies between in this confidence interval

(0.0338,0.0392).

<u>Answer:-</u>

<u>using t- distribution because is unknown,n<30,and the interest rates are not normally distributed.</u>

4 0

2 years ago

The average fuel efficiency of U.S. light vehicles for 2005 was 21 mpg. If the standard deviation of the population was 2.9 and

statuscvo [17]

Answer:

1) The probability that the mean mpg for a random sample of 25 light vehicles is 0.042341.

2) between 20 and 25 --> 21-25/2.9 = -1.38

Step-by-step explanation:

Problem #1:

Using the z-score formula, z = (x-μ)/σ/n, where x is the raw score = 20 mpg,μ is the population mean = 21 mpg , σ is the population standard deviation = 2.9, n = random number of samples.

= z = 20 - 21/2.9/√25
= z = -1/2.9/5
= z = -1.72414

<em>P-value from Z-Table:</em>

Problem #2:

6 0

1 year ago