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umka21 [38]
1 year ago
8

How did Mahler alter the original version of the tune for his symphony?

Biology
1 answer:
shutvik [7]1 year ago
7 0

Mahler alter the original version of the tune for his symphony - Both answers are correct - put it in a minor key AND added more pitches to the melody.

<h3>Mahler alter the original version of the tune for his symphony ; </h3>

Gustav Mahler's Symphony No. 1 in D major was primarily written between late 1887 and March 1888, while it contains music Mahler had written for earlier works. While Mahler was as second conductor at the Leipzig Opera in Germany, it was written. Mahler almost always referred to the piece as a symphony in his correspondence, but its first two performances were referred to as symphonic poems and tone poems in symphonic form, respectively. The piece's premiere took place in 1889 in Budapest's Vigadó Concert Hall, but it got poor reviews. For the second performance, which was given in Hamburg in October 1893, Mahler made some significant changes. Subsequent changes were made in the years before the first publishing, which happened in late 1898.

To know more about Mahler alter please click here : brainly.com/question/24940876

#SPJ9

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Earth Science <br><br> List and describe the three main parts of the earth
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The three main parts of the earth are the crust, the mantle, and the core.

Explanation:

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An animal cell has a nucleus but no cell wall.
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Choose one region on the world map. How does the climate their differ during El Niño and La Niña?
ratelena [41]

Answer:What are El Niño and La Niña?

El Niño and La Niña are opposite phases of a natural climate pattern across the tropical Pacific Ocean that swings back and forth every 3-7 years on average. Together, they are called ENSO (pronounced “en-so”), which is short for El Niño-Southern Oscillation.

The ENSO pattern in the tropical Pacific can be in one of three states: El Niño, Neutral, or La Niña. El Niño (the warm phase) and La Niña (the cool phase) lead to significant differences from the average ocean temperatures, winds, surface pressure, and rainfall across parts of the tropical Pacific. Neutral indicates that conditions are near their long-term average.

Maps of sea surface temperature anomaly in the Pacific Ocean during a strong La Niña (top, December 1988) and El Niño (bottom, December 1997). Maps by NOAA Climate.gov, based on data provided by NOAA View. large versions La Niña | El Niño

What happens during El Niño and La Niña?

During El Niño, the surface winds across the entire tropical Pacific are weaker than usual. Ocean temperatures in the central and eastern tropical Pacific Ocean are warmer than average, and rainfall is below average over Indonesia and above average over the central or eastern Pacific.

Rising air motion (which is linked to storms and rainfall) increases over the central or eastern Pacific, and surface pressure there tends to be lower than average.  Meanwhile, an increase in sinking air motion over Indonesia leads to higher surface pressure and dryness.  

walker circulation, ENSO, El Niño, convection, circulation, walker cell, tropical circulation, Pacific Walker Circulation, Pacific Walker Cell

Generalized Walker Circulation (December-February) anomaly during El Niño events, overlaid on map of average sea surface temperature anomalies. Anomalous ocean warming in the central and eastern Pacific (orange) help to shift a rising branch of the Walker Circulation to east of 180°, while sinking branches shift to over the Maritime continent and northern South America. NOAA Climate.gov drawing by Fiona Martin.

During La Niña, it’s the opposite. The surface winds across the entire tropical Pacific are stronger than usual, and most of the tropical Pacific Ocean is cooler than average. Rainfall increases over Indonesia (where waters remain warm) and decreases over the central tropical Pacific (which is cool). Over Indonesia, there is more rising air motion and lower surface pressure. There is more sinking air motion over the cooler waters of the central and eastern Pacific.

walker circulation, ENSO, La Niña, convection, circulation, walker cell, tropical circulation, Pacific Walker Circulation, Pacific Walker Cell

Generalized Walker Circulation (December-February) anomaly during La Niña events, overlaid on map of average sea surface temperature anomalies. Anomalous ocean cooling (blue-green) in the central and eastern Pacific Ocean and warming over the western Pacific Ocean enhance the rising branch of the Walker circulation over the Maritime Continent and the sinking branch over the eastern Pacific Ocean. Enhanced rising motion is also observed over northern South America, while anomalous sinking motion is found over eastern Africa. NOAA Climate.gov drawing by Fiona Martin.

Between the warm phase (El Niño) and cool phase (La Niña), scientists describe conditions as “ENSO-neutral.” Neutral means that the temperatures, winds, convection (rising air), and rainfall across the tropical Pacific are near their long-term averages.  

Walker Circulation - ENSO Neutral

Explanation:

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Newsweek in 1989 reported that 60% of young children have blood lead levels that could impair their neurological development. As
Kamila [148]

Answer:

The answer is 83.38%.

Explanation:

The probability of young children having blood levels that impair their neurological development is given as 60% in the question. To find the probability of at least 5 children out of 10 in a sample having said blood levels, we need to use the binomial probability.

n represents the total number of children in the sample so n = 10 and p is the probability of the children having blood levels causing the problem which is 60% so p = 0.6.

We want the probability of it being observed for 5 or more children and that is P(x\geq 5). If we subtract the P( x\leq 4) from 1, which is the probability of not observing the condition in 5 or more children, we will have the P(x\geq 5).

1 - P(x\leq 4) = 1 - pbinom(4, 10, 0.6) which are the probability range in the function, the sample size and the probability of observing the condition respectively.

The result is 1 - 0.1662 = 0.8338 which means that the probability that is asked is 83.38%.

I hope this answer helps.  

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