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never [62]
1 year ago
10

There are 60 people waiting for a river raft ride. Each raft holds

Mathematics
1 answer:
andrey2020 [161]1 year ago
8 0

If there are 60 people waiting for a river raft ride. Each raft holds

15 people. how Silvia's work can be used to find the number

of rafts needed is: total number of people/Number of people holded by  each raft.

<h3>Number of rafts needed</h3>

Using this formula

There are 136 people waiting for a river raft ride each raft holds 8 people.

Number of rafts needed=Number of people/Capacity of raft

Where:

Number of people = 60

Capacity of raft = 15 people

Let plug in the formula

Number of rafts needed=60/15

Number of rafts needed=4 rafts needed

Therefore if  raft holds 15 people. how Silvia's work can be used to find the number of rafts needed is: total number of people/<em>Number </em>of people holded by  each raft.

Learn more about Number of rafts needed here:brainly.com/question/8361379
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Sorry to be annoying again I just really suck at math and I haven't slept yet ​
Vesna [10]

Answer:

50.33 mi.

Step-by-step explanation:

<u>GIVEN :-</u>

Coordinates of :-

  • Home = (0 , 0)
  • School = (4 , 3)
  • Pizza place = (-8 , 2)
  • Movie Theater = (-4 , -6)
  • Park = (7 , -5)

<u>TO FIND :-</u>

  • Total distance travelled on Friday & Saturday.

<u>GENERAL FORMULAE TO BE USED IN THIS QUESTION :-</u>

Lets say there are two points A & B on a cartesian plane whose coordinates are (x₁ , y₁) & (x₂ , y₂).

Distance between A & B = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

<u>SOLUTION :-</u>

According to question ,

On Friday , you -

  • leave school and go to pizza palace. Distance travelled from school to pizza palace = \sqrt{(4 -(-8) )^2 + (3 - 2)^2} = \sqrt{(12)^2 + (1)^2} = \sqrt{145} ≈ 12.04 mi.
  • go to movie theater after pizza palace. Distance travelled from pizza palace to movie theater = \sqrt{[(-4) -(-8)]^2 + (-6 - 2)^2} = \sqrt{(4)^2 + (-8)^2} = \sqrt{80}= 4\sqrt{5} ≈ 8.94 mi.
  • come back to your home after the movies. Distance travelled from theater to home = \sqrt{[0-(-4)]^2 + (0 - 6)^2} = \sqrt{(4)^2 + (-6)^2} = \sqrt{52} = 2\sqrt{13} ≈ 7.21 mi.

⇒ <em>On Friday , total distance travelled = 12.04 + 8.94 + 7.21 = 28.19 mi.</em>

On Saturday , you -

  • go to park from your home. Distance travelled from home to park = \sqrt{(7 -0 )^2 + (-5 - 0)^2} = \sqrt{(7)^2 + (-5)^2} = \sqrt{74} ≈ 8.6 mi.
  • go to school after going to park. Distance travelled from park to school = \sqrt{(4 -7 )^2 + [3 - (-5)]^2} = \sqrt{(-3)^2 + (8)^2} = \sqrt{73} ≈ 8.54 mi.
  • go to home after playing basketball in school. Distance travelled from school to home = \sqrt{(0 -4 )^2 + (0 - 3)^2} = \sqrt{(-4)^2 + (-3)^2} = \sqrt{25} = 5 mi.

⇒ <em>On Saturday , total distance travelled = 8.6 + 8.54 + 5 = 22.14 mi.</em>

∴ Total distance travelled on Friday & Saturday = 28.19 + 22.14 = 50.33 mi.

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Solve 3(x + 5) = 2x + 35
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Explanation:

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The monthly fees for the local pool are $8 per month
Liono4ka [1.6K]

Given:

Monthly fees for the local pool are $8 per month  and $2 per visit.

Hector pays $34 in pool fees total for  the month.

To find:

The number of times he visit the pool.

Solution:

We have,

Monthly fee of pool = $8

Additional fee = $2 per visit

Let Hector visit x times.

Additional fee for x times = $2x

Total fee = Monthly fee + Additional fee

34=8+2x

34-8=2x

26=2x

Divide both sides by 2.

\dfrac{26}{2}=x

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Therefore, Hector visit the pool 13 times.

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