1 (8/9) = 1.88888888
3 (11/12) = 3<span><span>.9166666667
</span>
</span>
3<span>.91666 / </span>1.8888 =
<span>
<span>
<span>
2.0735294118
</span>
</span>
</span>
So, she can make 2 batches of cupcakes.
Answer:
0.23
Step-by-step explanation:
The question is incomplete! Complete question along with answer and step by step explanation is provided below.
Question:
The lifetime (in hours) of a 60-watt light bulb is a random variable that has a Normal distribution with σ = 30 hours. A random sample of 25 bulbs put on test produced a sample mean lifetime of = 1038 hours.
If in the study of the lifetime of 60-watt light bulbs it was desired to have a margin of error no larger than 6 hours with 99% confidence, how many randomly selected 60-watt light bulbs should be tested to achieve this result?
Given Information:
standard deviation = σ = 30 hours
confidence level = 99%
Margin of error = 6 hours
Required Information:
sample size = n = ?
Answer:
sample size = n ≈ 165
Step-by-step explanation:
We know that margin of error is given by
Margin of error = z*(σ/√n)
Where z is the corresponding confidence level score, σ is the standard deviation and n is the sample size
√n = z*σ/Margin of error
squaring both sides
n = (z*σ/Margin of error)²
For 99% confidence level the z-score is 2.576
n = (2.576*30/6)²
n = 164.73
since number of bulbs cannot be in fraction so rounding off yields
n ≈ 165
Therefore, a sample size of 165 bulbs is needed to ensure a margin of error not greater than 6 hours.
Answer:
Otieno's age in 4 years: 
Kidole's age in 4 years: 
Step-by-step explanation:
= Otieno's age
= Kidole's age
Their ages will increase by 4 years when 4 years pass.
= Otieno's age in 4 years
= Kidole's age in 4 years
= Kidole's age in 4 years (after simplifying the expression)
I hope this helps!
