converted to fraction in lowest terms is 
<em><u>Solution:</u></em>
Given that we have to convert
to fraction in lowest terms
Let us first convert the mixed fraction 
Multiply the whole number part by the fraction's denominator.
Add that to the numerator.
Then write the result on top of the denominator.
Therefore,


Now convert 77.5 % to fraction
So we have to convert percentage to fraction
Divide the percentage by 100 to get a decimal number

Use that decimal number as the numerator of a fraction. Put a 1 in the denominator of the fraction
Count the number of places to the right of the decimal. If you have x decimal places then multiply numerator and denominator by 

Simplify and reduce the fraction to lowest terms

Thus the given percentage is converted to fraction in lowest terms
The decimal point should move all the way behind '4'. Therefore the answer is 8714.0
Jordan should have 72 stamps. since Tully has 1/3 of Jordans collection, you multiply 24 by 3 to get 72
The equations (2) and (3) you referred to are unavailable, but it is clear that you are trying to show that two set of solutions y1 and y2, to a (second-order) differential equation are solutions, and form a fundamental set. This will be explained.
Answer:
SOLUTION OF A DIFFERENTIAL EQUATION.
Two functions y1 and y2 are set to be solutions to a differential equation if they both satisfy the said differential equation.
Suppose we have a differential equation
y'' + py' + qy = r
If y1 satisfies this differential equation, then
y1'' + py1' + qy1 = r
FUNDAMENTAL SET OF DIFFERENTIAL EQUATION.
Two functions y1 and y2 are said to form a fundamental set of solutions to a second-order differential equation if they are linearly independent. The functions are linearly independent if their Wronskian is different from zero.
If W(y1, y2) ≠ 0
Then solutions y1 and y2 form a fundamental set of the given differential equation.
Total possible outcomes = 36
Total possible outcomes with sum equal to 4 = 3
{1, 3} {2, 2}, (3, 1}
P(sum equal to 4) = 3/36 = 1/12
If you throw it 1000 times,
Number of times expected to have a sum of 4 = 1/12 x 1000 = 83 times
Answer: About 83 times