We toss two dice 1,000 times. How many times do we expect to have the sum of the two dice equal to 4?

1 answer:

5 0

Total possible outcomes = 36
Total possible outcomes with sum equal to 4 = 3
{1, 3} {2, 2}, (3, 1}

P(sum equal to 4) = 3/36 = 1/12

If you throw it 1000 times,
Number of times expected to have a sum of 4 = 1/12 x 1000 = 83 times

Answer: About 83 times

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