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ira [324]
3 years ago
5

We toss two dice 1,000 times. How many times do we expect to have the sum of the two dice equal to 4?

Mathematics
1 answer:
Delicious77 [7]3 years ago
5 0
Total possible outcomes = 36
Total possible outcomes with sum equal to 4 = 3
{1, 3} {2, 2}, (3, 1}

P(sum equal to 4) = 3/36 = 1/12

If you throw it 1000 times,
Number of times expected to have a sum of 4 = 1/12 x 1000 = 83 times

Answer: About 83 times
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You roll a six sided die. What is the probability of rolling a 1 or a number greater than 4.
Romashka [77]

A. 1/2

This is because there are 6 possible outcomes. 1, 2, 3, 4, 5, and 6.

The probability of rolling 1, 5, and 6 is 3 out of 6 (3/6)

3/6 reduced is 1/2.

3 0
3 years ago
What is the simplified value of the expression below? 4.2+0.6/3-5(0.9-0.5) will mark the brainliest
makkiz [27]

Hi!

4.2+0.6/3-5(0.9-0.5) = 4.2 + 0.2 - 5*0.4 = 4.4 - 2 = 2.4

Hope this helps!

4 0
3 years ago
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Elsa drove 603 miles in9 hours at the same rate how many miles would she drive in 7 hours
bezimeni [28]

Answer:

469 miles

Step-by-step explanation:

divide 603 by 9 which is 67, multiply 7 into 67 and the answer into that is 469

hope that helps:)

4 0
3 years ago
Please i need help finishing this test i’ll give brainly to a correct answer
rjkz [21]

imma go with my gut and say b :?

7 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST!
pav-90 [236]

Answer:

1, 5, 17, 53, 161

Step-by-step explanation:

Given:

  • a_1=1
  • a_n=3a_{n-1}+2

First five terms of the sequence:

a_1=1

a_2=3a_1+2=3(1)+2=5

a_3=3a_2+2=3(5)+2=17

a_4=3a_3+2=3(17)+2=53

a_5=3a_4+2=3(53)+2=161

7 0
2 years ago
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