A jar of jelly beans contains 50 red gumballs , 45 yellow gumballs, and 30 green gumballs. You reach into the jar and randomly
select a jelly bean, then select another without
putting the first jelly bean back. What is the
probability that you draw two red jelly beans? This is Dependent because you didnt put the other jelly bean in thus changing the total nmber of jelly beans.
A jar of jelly beans contains 50 red gumballs<span> , 45 yellow gumballs, and 30 green gumballs. You reach into the jar and randomly select a jelly bean, then select another while replacing the first jelly bean back. What is the probability that you draw two red jelly beans? This is Independent because you put the other jelly bean in thus keeping the total number of jelly beans.</span>
Answer:
yly ls an integer that is the answer
Answer:
a^3-b^2
3^3-1-2^2
3*3*3-1/2*1/2*1/2
or
3*3*3-0.5*0.5*0.5
27-0.125
=26.875
Step-by-step explanation:
Answer:
40,000/100=400
Step-by-step explanation:
Answer:
-6(x-2)=-7(x-3) = False x = 9
Step-by-step explanation:
Solve for x:
-6 (x - 2) = -7 (x - 3)
Expand out terms of the left hand side:
12 - 6 x = -7 (x - 3)
Expand out terms of the right hand side:
12 - 6 x = 21 - 7 x
Add 7 x to both sides:
7 x - 6 x + 12 = (7 x - 7 x) + 21
7 x - 7 x = 0:
7 x - 6 x + 12 = 21
7 x - 6 x = x:
x + 12 = 21
Subtract 12 from both sides:
x + (12 - 12) = 21 - 12
12 - 12 = 0:
x = 21 - 12
21 - 12 = 9:
Answer: x = 9