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krek1111 [17]
3 years ago
7

Work out the size of the interior angle DEA. Picture provided below, please help.

Mathematics
1 answer:
Alik [6]3 years ago
3 0
I'm working on helping you figure this one out. By chance could you find the angle measure of B?
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How do you get why by itself in this equation? 4x+5y=5
Alja [10]

Answer:

first we get y on one side by itself.

4x+5y=5

we'll move x to the other side.

4x-4x+5y=5-4x

simplify.

5y=5-4x

now we get rid of the coefficient on y.

5y/5=(5-4x)/5

simplify.

y=5/5-4x/5

y=1- \frac{4}{5}x

The answer is y=1-\frac{4}{5}x

6 0
2 years ago
the lengths of the sides of a triangle are consecutive odd integers.if the perimeter of the triangle is 27 what is are the lengt
Umnica [9.8K]
The lengths of each side are 9
5 0
3 years ago
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1015
ludmilkaskok [199]

Answer:

A shirt cost £5 while the hat cost £2.

Step-by-step explanation:

What I did was guess and check until i found the amount of each item. You can also use a table to this.

6 0
3 years ago
If the angles of a triangle are (2y - 5)degrees, (y + 20)degrees, and (3y-5) degrees what are the values of the angles​
NNADVOKAT [17]

Answer:

<h3>\boxed{ \boxed{ \bold{ \sf{51.68  \: , \: 48.34 \:,  \: 80.02}}}}</h3>

Step-by-step explanation:

Let's solve:

As we know that the sum of angles of traingle adds to 180°

\sf{2y - 5 + y + 20 + 3y - 5 = 180}

Collect like terms

⇒\sf{6y - 5 + 20 - 5 = 180}

⇒\sf{6y   + 15 - 5 = 180}

⇒\sf{6y + 10 = 180}

Move constant to right hand side and change it's sign

⇒\sf{6y = 180 - 10}

Calculate the difference

⇒\sf{6y = 170}

Divide both sides of the equation by 6

⇒\sf{ \frac{6y}{6}  =  \frac{170}{6} }

Calculate

⇒\sf{y = 28.34}

Now, let's replace the value:

⇒\sf{2y - 5 = 2 \times 28.34 - 5 = 51.68}

⇒\sf{y + 20 = 28.34  + 20 = 48.34}

⇒\sf{3y - 5 = 3 \times 28.34 - 5 = 80.02}

Hope I helped!

Best regards!!

8 0
2 years ago
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Consider the two triangles.
gizmo_the_mogwai [7]

Answer:

Show that the ratios StartFraction UV/XY, WU/ZX, and WV/ZY are equivalent.

Step-by-step explanation:

I just took the quiz and got it right. Hope this helps :)

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