All categories

1 year ago

M&M’s and Skittles was

Mathematics

1 answer:

ipn [44]1 year ago

8 0

Answer:
SKITTLES: 35
M&MS: 20

Step-by-step explanation:

First, I multiplied how much is required for to be even, which is 27.5.

So just double the m&m's, which is 55, then subtract the 55 m&m's by 20, and then you get 35 skittles.

Then you have 20 bags of m&m's left over, hope this is correct and helpful.

You might be interested in

If f(x) = 4x + 21 and g(x) = 2x + 2 what is f[g(7)]

Nana76 [90]

Answer:

we conclude:

$f(g(7)) =85$

Step-by-step explanation:

Given

$f(x) = 4x + 21$

$g(x) = 2x + 2$

To determine

$f(g(7)) =?$

In order to determine f(g(7)), the first step we need to do is to determine g(7)

so substitute x = 7 in g(x) = 2x + 2

$g(x) = 2x + 2$

$g(7) = 2(7) + 2$

$g(7) = 14 + 2$

$g(7) = 16$

so now we have

$f(g(7)) =f(16)$

The next step to do is to substitute x = 16 in f(x) = 4x + 21

$f(x) = 4x + 21$

$f(16) = 4(16) + 21$

$f(16) = 64 + 21$

$f(16) = 85$

so we have

$f(g(7)) =f(16)=85$

Therefore, we conclude:

$f(g(7)) =85$

6 0

3 years ago

Read 2 more answers

Determine whether the equation represents direct, inverse, joint, or combined variation.

Dominik [7]

Answer: The retort to the peculiar proposed interrogate is definitively identified as ‘Joint Variation’, interchangeably acknowledged as ‘Combined Variation’.

Step-by-Step Explanation:

Given the mathematical statement,
Y = 4x^3z^3

Such coherently demonstrates the principle of a foreign variable, ‘y’, which whom varies directly as the product of at least two distinct or distinguishable quantities occur.

The mentioned is the precise definition of Joint Variation, where ‘y’ is jointly proportional to the product of the minimum agglomerate of two quantities, whilst a presence of a nonzero constant, k.

*I hope this helps.

5 0

3 years ago

Following are measurements of soil concentrations (in mg/kg) of chromium (Cr) and nickel (Ni) at 20 sites in the area of Clevela

WINSTONCH [101]

Answer:

a) see attached

b) see attached

Step-by-step explanation:

There is existence of outlier in the Ni data and there is none is Cr data.

########################################

# You can try this out in R programming

cr = c(34, 1, 511, 2, 574, 496, 322, 424, 269, 140, 244, 252, 76, 108, 24,