Answer:
Gọi AH là đường cao kẻ từ A đến BC
Xét tam giác AHC vuông tại H
Suy ra AH = HC. cotA= 9.cot35° = 12,9
Xét tam giác AHB vuông tại H
Suy ra BH = AH.tanA = 12,9.tan61°=23,37
Ta có BC= HC+ HB= 9+23,27 =32,27
Diện tích tam giác ABC = 1/2 × AH ×BC= 1/2 ×12,9×32,27=208,1415
The answer
the complement of the question is
What is the value of y?
2
5
7
<span>8
</span>
According to the image, HKJ and FGH are similar, we can apply the theorem of thales
since GK and GF are parallels, so
HK / HF = HJ / HG = KJ / GF and as we see on the figure, HK = HF /2, this implies 2HK =HF
HK / 2HK = KJ / GF it is equivalent to 1/2 = 2y+5 / 5y +3
likewise, equivalent to 5y +3 = 4y +10, 5y-4y = 10-3, and y = 7
so the answer is 7
3/4 = 45/60, 4/5 = 48/60, 2/3 = 40/ 60
You are welcome
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yes the answer is ratio you are correct
