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adoni [48]
1 year ago
9

Find the identical expression for cos(A+B) /sinAcosB

Mathematics
1 answer:
Igoryamba1 year ago
7 0

EXPLANATION

Apply the fraction rule:

\frac{a\pm b}{c}=\frac{a}{c}\pm\frac{b}{c}\frac{\sin(a)+\sin(b)}{\sin(a)\cos(b)}=\frac{\sin(a)}{\sin(a)\cos(b)}+\frac{\sin (b)}{\sin (a)\cos (b)}=\frac{\sin(a)}{\sin(a)\cos(b)}+\frac{\sin (b)}{\sin (a)\cos (b)}

Cancel:

\frac{\sin (a)}{\sin (a)\cos (b)}

Cancel the common factor: sin(a)

\frac{1}{\cos (b)}=\frac{1}{\cos(b)}+\frac{\sin (b)}{\sin (a)\cos (b)}

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Which of the following correctly justifies statement 4 of the two-column proof?
slavikrds [6]

Answer:

D.Transitive property of equality

Step-by-step explanation:

We are given that segment JK is parallel to segment LM

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3 years ago
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8 0
1 year ago
Translate into an equation:
tatiyna
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