So increased weight = 92-80 = 12
so ℅ = 12×100/80 = 15
so his weight is increased by 15℅ !!
The value of the collection originally was $1,000,000
What was the original value of the collection?
The original value of the collection is not known, hence, it is represented by X
The increase in value by $50,000 means that the value is X+$50,000
Now, when the error was discovered, it is now worth half of the value previously
The new value is (X+$50,000)*0.5
New value=(X+$50,000)*0.5
The new value at this point is $525,000
$525,000=(X+$50,000)*0.5
$525,000/0.5=X+$50,000
$1,050,000=X+$50,000
X=$1,050,000-$50,000
Find out more about change in value on:brainly.com/question/13097163
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Answer:
3 miles
Step-by-step explanation:
1/2 hour is 30 minutes so 1.5 x 2 is 3
Answer:
a) 
b) 
c) ![r=\frac{7(30095)-(4210)(49)}{\sqrt{[7(2595100) -(4210)^2][7(354) -(49)^2]}}=0.7503](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B7%2830095%29-%284210%29%2849%29%7D%7B%5Csqrt%7B%5B7%282595100%29%20-%284210%29%5E2%5D%5B7%28354%29%20-%2849%29%5E2%5D%7D%7D%3D0.7503)
Step-by-step explanation:
Data given
x: 500, 700, 750, 590 , 540, 650, 480
y: 7.00, 7.50 , 9.00, 6.5, 7.50 , 7.0, 4.50
Part a
We want to create a linear model like this :
Wehre
And:
With these we can find the sums:
And the slope would be:
Nowe we can find the means for x and y like this:
And we can find the intercept using this:
And the line would be:
Part b
The correlation coefficient is given by:
![r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7Bn%28%5Csum%20xy%29-%28%5Csum%20x%29%28%5Csum%20y%29%7D%7B%5Csqrt%7B%5Bn%5Csum%20x%5E2%20-%28%5Csum%20x%29%5E2%5D%5Bn%5Csum%20y%5E2%20-%28%5Csum%20y%29%5E2%5D%7D%7D)
For our case we have this:
n=7 
The determination coefficient is given by:
Part c
The maximum positive value that the correlation coefficient can have is 1.
Thus, 0.88 is pretty close, indicating a positive slope for the regression line and points lying close to that line.
