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11 months ago

Suppose m<7 = 96 find m<2 and m< 4

Mathematics

1 answer:

Vsevolod [243]11 months ago

6 0

Answer:

Answer down below!

Step-by-step explanation:

If we draw this out, we already know that m<7 = 96

Using what we already know, we can figure out the rest

m<6 also equals 96 because m<7 and m<6 are verticle angles

m<3 also equals 96 because m<6 and m<3 are opposite interior angles

m<2 also equals 96 because m<3 and m<2 are verticle angles

Now, to find m<4, simply subtract 96 from 180. That should give you 84

Thus, m<2 = 96 and m<4 = 84

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<h3>Answer: -10 and -40</h3>

===============================================================

Explanation:

a = 200 = first term

d = -30 = common difference

Tn = nth term

Tn = a + d(n-1)

Tn = 200 + (-30)(n-1)

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Rounding up to the nearest whole number gets us $n \ge 8$

So Tn starts to turn negative when n = 8

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and lastly

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