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stiv31 [10]
3 years ago
12

Find the value of a2 + 3b , when a = -2 and b = 5​

Mathematics
2 answers:
Sloan [31]3 years ago
5 0

\huge\mathfrak {Answer}

Value of

a = -2 and

b = 5

=》a2 + 3b

=》2 × 2 + 3 × 5

=》4 + 14

=》18

Thanks

zimovet [89]3 years ago
5 0

{\huge {\mathfrak {\orange {Answer :}}}}

We have, a = ( - 2) and b = 5

So, a^2 + 3b

= ( - 2)^2 + 3 * 5

= 4 + 15

= 19

➡️ 19 is your answer

That's it..

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Is the equation conditional, an identity, or a contradiction? y - 11 + 3y = 6y + 4
ipn [44]

Answer:

The equation is a conditional.

y = 7.5

Step-by-step explanation:

y - 11 + 3y = 6y + 4

4y - 11 = 6y + 4

4y - 4y - 11 = 6y - 4y + 4

- 11 = 2y + 4

- 11 - 4 = 2y + 4 - 4

2y = - 15

2y ÷ 2 = - 15 ÷ 2

y = - 7.5

8 0
3 years ago
a car costs 25,750.00 and depreciates in value 20%per year. how much will the car be worth in 5 years?
andriy [413]
In five years the car will be worth $9,472.90
3 0
3 years ago
Suppose that you are given a bag containing n unbiased coins. You are told that n-1 of these coins are normal, with heads on one
gladu [14]

Answer:

The (conditional) probability that the coin you chose is the fake coin is 2/(1 + n)

Step-by-step explanation:

Given

Total unbiased coin = n

Normal coins =n - 1

Fake = 1

The (conditional) probability that the coin you chose is the fake coin is represented by

P(Fake | Head)

And it's calculated as follows;

P(Fake | Head) = P(Fake, Head) ÷ P(Head) ----- (1)

Where P(Fake, Head) = P(Fake) * P(Head | Fake)

P(Fake) = 1/n --- because only one is fake

P(Head | Fake) = n/n because all coins (including the fake) have head

So, P(Fake, Head) = P(Fake) * P(Head | Fake) becomes

P(Fake, Head) = 1/n * n/n

P(Fake, Head) = 1/n

P(Head) is calculated by

P(Fake) * P(Head | Fake) + P(Normal) * P(Head | Normal)

P(Fake) * P(Head | Fake) = P(Fake, Head) = 1/n (as calculated above)

P(Normal) * P(Head | Normal) = ½ * (n - 1)/n ----- considering that the coin also has a tail with equal probability as that of the head.

Going back to (1)

P(Fake | Head) = P(Fake, Head) ÷ P(Head) becomes

P(Fake | Head) = (1/n) ÷ ((1/n) + (½(n-1)/n))

= (1/n) ÷ ((1/n) + (½(n-1)/n))

= (1/n) ÷ (1/n + (n - 1)/2n)

= (1/n) ÷ (2 + n - 1)/(2n)

= (1/n) ÷ (1 + n)/(2n)

= (1/n) * (2n)/(1 + n)

= 2/(1 + n)

Hence, the (conditional) probability that the coin you chose is the fake coin is 2/(1 + n)

5 0
3 years ago
If on January 1,2015 you decide to read one thousand and one night over the next 1,001 night an which date would you finally fin
SVETLANKA909090 [29]
Starting January 1, 2015, there are 364 remaining nights.
From 1,001 nights, it will be 637 nights left.

In 2016, there are 366 nights. Subtract it to 637 nights left, you will get 271 nights left.
In 2017, 271 is lesser than 365.
From January to August, the nights left is 28.
<span>
So the date will be September 28, 2017.</span>
6 0
3 years ago
mike drove to a frineds house at the rage of 40 mph. he returned hoke by the dsne route at 45 mph the driving time for the round
wolverine [178]

Let the distance be x miles

Time = Distance / speed

Time taken by Mike to go to his friend's house = x / 40 hours

Time taken by him to return = x / 45 hours

Total time = x / 40 + x / 45 = 4 hours

= 9x + 8x = 1440 miles

17x = 1440

= x = 1440 ÷ 7

= x = 84.706

Time taken to return home = 84.706 /45= 1.882 hours .

Therefore , Mike took 1.882 hours to reach home .

8 0
3 years ago
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