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snow_tiger [21]
1 year ago
9

The grid shows Figure Q and its image Figure Q′ after a transformation.

Mathematics
1 answer:
Svetach [21]1 year ago
8 0

The transformation of pentagon Q to pentagon Q' is a clockwise rotation of 180° about the origin.

<h3>What is transformation?</h3>

A transformation is a general term for four specific ways to manipulate the shape or position of a point, a line, or a geometric figure.

We have,

Coordinates of a pentagon Q.

(2, 4), (3, 7), (7, 5), (5,4), and (4,2).

Coordinates of pentagon Q'.

(-2, -4), (-3, -7), (-7, -5), (-5,-4), and (-4,-2).

We see that the coordinates of each point of the pentagon Q have changed their position as negative coordinates in pentagon Q'

The coordinates of pentagon Q are in (x, y) which can be assumed to be in the first quadrant of the coordinate plane.

The coordinates of pentagon Q' are in (-x, -y) which is in the 3rd quadrant.

From the first quadrant to 3rd quadrant there is a rotation of 180°.

Thus the transformation of pentagon Q to pentagon Q' is a clockwise rotation of 180° about the origin.

Learn more about transformation here:

brainly.com/question/4458799

#SPJ1

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antoniya [11.8K]

Answer:

oof

Step-by-step explanation:

7 0
3 years ago
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Write the equation that modeled the sequence 63,-21,7,-7/3,7/9
Ilya [14]

Answer:

an = 63(-1/3)^(n-1)

Step-by-step explanation:

This is a geometric sequence with first term 63 and common ratio -1/3.

The equation for the nth term  is

an = 63(-1/3)^(n-1).

6 0
3 years ago
1. In this figure, line m is parallel to line n, and p is a
mariarad [96]

Answer:

4

Step-by-step explanation:

picture attached as explanation

We can see through alternate interior and exterior angles, corresponding angles, and vertical angles what the measures are.

4 0
3 years ago
Anyone know the answer?? ​
Serggg [28]

Answer:

the second option

Step-by-step explanation:

in ax²+bx+c = 0:

x = \frac{-b+-\sqrt{b^2-4ac} }{2a}

subtract both sides by 6 to get to this form, as the right side will be left with 0

6x² + 8x - 6 = 0

here, the coefficient for x² (a) is 6, the coefficient for x (b) is 8, and the remaining number added on (c) is -6

plugging our numbers into the formula, we get

x = \frac{-8+-\sqrt{(-8)^2-4(6)(-6)} }{2(6)}\\= \frac{-8+-\sqrt{64-(-144)} }{12} \\= \frac{-8+-\sqrt{208} }{12} \\ = \frac{-8+\sqrt{208} }{12} or \frac{-8-\sqrt{208} }{12}\\= 0.53518375848 or -1.86851709182\\= approximately -1.87, 0.54

8 0
2 years ago
????????????????????/?????????????????????????ching chong
Kitty [74]

Answer:

I think ---- Independent

6 0
3 years ago
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