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3 years ago

What is a algebraic expression

Mathematics

2 answers:

alexgriva [62]3 years ago

8 0

Answer: An algebraic expression is a mathematical phrase that can contain numbers and/or variables.

Step-by-step explanation:

Zarrin [17]3 years ago

4 0

Answer:

Algebraic expression is an expression built up from integer constants, variables, and the algebraic operations

Step-by-step explanation:

You might be interested in

what is the slope and equation of a line that is perpendicular to the y-axis passing through (-5,-3)?

Illusion [34]

Answer:

Slope is m=0

$y=-3$

Step-by-step explanation:

The slope of any line that is perpendicular to the y-axis is zero.

The reason is that any line that is perpendicular to the y-axis is also parallel to the x-axis and the slope of the x-axis is zero.

The equation of any line perpendicular to the y-axis is and passes through (a,b) is y=b.

The given point is (-5,-3) hence the required equation is

$y=-3$

3 0

2 years ago

Without finding the inverse of the function determine the range of the inverse of F(x) = the square root of x-4

Nastasia [14]

The rang of an inverse function is the domain of the normal function
So you just gotta find the domain of that which is x is greater than or equal to 0

3 0

3 years ago

If anyone knows about definite integrals for calculus then please I request help! I

kicyunya [14]

Answer:

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

U-Substitution

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx$

Step 2: Integrate Pt. 1

Identify variables for u-substitution.

Set u: $\displaystyle u = 4x^{-2}$
[u] Differentiate [Basic Power Rule, Derivative Properties]: $\displaystyle du = \frac{-8}{x^3} \ dx$
[Bounds] Switch: $\displaystyle \left \{ {{x = 9 ,\ u = 4(9)^{-2} = \frac{4}{81}} \atop {x = 5 ,\ u = 4(5)^{-2} = \frac{4}{25}}} \right.$

Step 3: Integrate Pt. 2

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^9_5 {\frac{-8}{x^3}e^\big{4x^{-2}}} \, dx$
[Integral] U-Substitution: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^{\frac{4}{81}}_{\frac{4}{25}} {e^\big{u}} \, du$
[Integral] Exponential Integration: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}(e^\big{u}) \bigg| \limits^{\frac{4}{81}}_{\frac{4}{25}}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8} \bigg( e^\Big{\frac{4}{81}} - e^\Big{\frac{4}{25}} \bigg)$
Simplify: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

4 0

2 years ago

Please answer my question .q bo 4 d and e

sdas [7]

4 (e)
sin^8 x - cos^8 x
= (sin^4 x + cos^4 x)(sin^4 x - cos^4 x)
= (sin^4 x + cos^4 x)(sin^2 x - cos^2x)(sin^2 x +cos^2 x)
= (sin^4x + cos^4 x)( sin^2 x- cos^2 x)

Sorry I cant do 4 (d).

5 0

3 years ago

Write the following fractions in word. 3/4, 1/5, 3/4, 1 3/5.. please help me

Alik [6]

Answer:

"In word" as in word form?

3/4 = three fourths

1/5 = one fifth

3/4 = three fourths (again?)

1 3/5 = one and three fifths

4 0

2 years ago