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Ipatiy [6.2K]
1 year ago
4

Use a table to compute the product below. (2^x2 + 5x + 3)(4x - 8)

Mathematics
1 answer:
antoniya [11.8K]1 year ago
4 0

For any product in form (a+b+c)*(d+e), we solve if multiplying each term from (a+b+c) by each term from (d+e) as follows:

(a+b+c)*(d+e) = ad + bd + cd + ae + be + ce

Aplying that rule on the product (2x^2 + 5x + 3)*(4x - 8), we have

(2x^2 + 5x + 3)*(4x - 8) = (4x)*(2x^2) + (4x)*(5x) + (4x)*(3) + (-8)*(2x^2) + (-8)*(5x) + (-8)*(3) = 8x^3 + 20x^2 + 12x - 16x^2 - 40x - 24 = 8x^3 + 4x^2 - 28x - 24

(2x^2 + 5x + 3)*(4x - 8) = 8x^3 + 4x^2 - 28x - 24

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