Question

BCDE is a Rhombus. BD=28, and CE=20 what is ED. ?

Answer 1

Given:

BCDE is a Rhombus.

$BD=28\text{ ; CE=20}$

Let 'a' be the side of a rhombus.

$\begin{gathered} a=\frac{\sqrt[]{BD^2+CE^2}}{2} \\ a=\frac{\sqrt[]{28^2+20^2}}{2} \\ a=\frac{\sqrt[]{784+400}}{2} \\ a=\frac{\sqrt[]{1184}}{2} \\ a=17.2 \end{gathered}$$ED=17.2$

Option d is the final answer.