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Alex
2 years ago
8

Use the result (a+b)²=a²+2ab+b² to find the value of 49²+98+1

Mathematics
1 answer:
Leto [7]2 years ago
5 0

Answer:

2500

Step-by-step explanation:

a² + 2ab + b²

49² + 98 + 1

Comparing terms

a²= 49²

a= 49

2ab = 98

2× 49 × b = 98

98b = 98

b= 98/98

b = 1

or

b²= 1

b=√1

b= 1

a=49 and b= 1

Hence (a+b)²= (49+1)²

50²= 2500

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Answer:

OPTION B: 162, 486, 1458

Step-by-step explanation:

The given sequence is 2, 6, 18, 54, . . .

It is a geometric sequence and the common difference is 3.

The general form of a geometric sequence is: a, ar, ar², ar³, . . .

Here a = 2 and r = 3.

$ n^{th} $ term of a Geometric progression is $ ar^{n - 1} $.

Note that the fourth term is 54.

i.e., $ ar^3 = 54 $

$ \implies ar^4 = ar^3 . r = 54 . 3 = 162 $.

Similarly, $ ar^6 = 162 \times 3 = 486 $.

Also, $ ar^7 = ar^6 . r = 486 \times 3 = 1458 $.

Hence, OPTION B is the answer.

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2 years ago
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Step-by-step explanation:

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3 years ago
Explain why the quadratic relation y=2x^2+3x+5 would have no zeros
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Complete the square to rewrite the quadratic:

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