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Musya8 [376]
1 year ago
12

Find the degree of 3x

^{3} y^{2} " alt="3 {x}^{3} y^{2} " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
GrogVix [38]1 year ago
8 0

Answer:

I dont know

Step-by-step explanation:

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I have no idea how to do this.
Anastasy [175]
The trick to solving problems with mixed units is to convert all of them into one unit or another, so:

There are 12 inches in a foot, so 72 inches = 6 feet.
To find the perimeter of a polygon, sum its sides.
Perimeter = 2 + 5 + 6 = 13 feet.

To find the area of a right triangle (which I assume the one in the picture is), we can use the following equation: A = 0.5 * base * height
There are 3 feet to one yard, so 6 feet = 2 yards.
Area = 0.5 * 2 * 1 = 1 yard^2
7 0
3 years ago
A central angle in a circle with a radius of 7in. intercepts an arc with a length of 9in. What is the radian measure of the cent
Vitek1552 [10]
A central angle in a circle with a radius of 7in. intercepts an arc with a length of 9in. What is the radian measure of the central angle?

8 0
3 years ago
Rob spent $38 on shirts. Tee shirts cost $4 and long sleeve shirts cost $5. If he bought a total of 8 then how many of each kind
KATRIN_1 [288]

Answer:

2 long sleeve and then 7 short sleeve

3 0
3 years ago
If a square has an area of 225 square feet what is the length of each side
sdas [7]
The area of the square: A=a^2

where "a" is a length of side.


Therefore:
A=225\ ft^2\ and\ A=a^2\Rightarrow a^2=225\Rightarrow a=\sqrt{225}\Rightarrow \boxed{a=15\ (ft)}
3 0
3 years ago
Define fn : [0,1] --> R by the
sasho [114]

Answer:

The sequence of functions \{x^{n}\}_{n\in \mathbb{N}} converges to the function

f(x)=\begin{cases}0&0\leq x.

Step-by-step explanation:

The limit \lim_{n\to \infty }c^{n} exists and converges to zero whenever \lvert c \rvert. But, if c=1 the sequence \{c^{n}\} is constant and all its terms are equal to 1, then converges to 1. Using this result, consider the sequence of functions \{f_{n}\} defined on the interval [0,1] by f_{n}(x)=x^{n}. Then, for all 0\leq x we have that \lim_{n\to \infty}x^{n}=0. Now, if x=1, then \lim_{n\to \infty }x^{n}=1. Therefore, the limit function of the sequence of functions is

f(x)=\begin{cases}0&0\leq x.

To show that the convergence is not uniform consider 0. For any n>1 choose x\in (0,1)  such that \varepsilon^{1/n}. Then

\varepsilon

This implies that the convergence is not uniform.

8 0
3 years ago
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