Note: Consider the side of first triangle is TQ instead of TA.
Given:
Triangles TQM and TPN which share vertex T.
To find:
The theorem which shows that 
.
Solution:
In triangle TQM and TPN,
[Given]
[Given]
[Given]
Since two sides and their including angle are congruent in both triangles, therefore both triangles are congruent by SAS postulate.
[SAS]
Therefore, the correct option is C.
Answer:
y = -0.83x - 2
Step-by-step explanation:
Slope intercept form is y = mx+b.
M is the slope: In this case the slope (rise/run) is 10/12. However, the slope is decreasing is that would make it negative.
Now we have: y = -0.83x + b
B represents the y-intercept. The y-intercept here is -2. So our final equation is:
y = -0.83x - 2
if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.
so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.
so... for example a parallel to <-12, 5> is say hmmm < -144, 60>, if you simplify that fraction, you'd end up with <-12, 5>, since all we did was multiply both coordinates by 12.
or using a unit vector for those above, then
Answer:
The exact length of the third side would be 9.
Step-by-step explanation:
To find the length of the triangle, just add the height (6) and the base (3) which equals 9.
