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mafiozo [28]
1 year ago
14

Hi can someone please help me with my math work im very behind

Mathematics
1 answer:
Ipatiy [6.2K]1 year ago
5 0

The volume of soup in the cylindrical can is 100.48 inches cube.

<h3>How to find the volume of a cylindrical can?</h3>

We have to find the volume of the soup in a cylindrical can of height 8 inches and 4 inches across the lid.

The volume of the soup is the volume of the cylindrical can.

Therefore,

volume of the cylindrical can = πr²h

where

  • r = radius of the cylinder
  • h = height of the cylinder

Therefore,

h = 8 inches

r = 4 / 2 = 2 inches

volume of the soup in the cylindrical can = πr²h

volume of the soup in the cylindrical can = π × 2² × 8

volume of the soup in the cylindrical can = π × 4 × 8

volume of the soup in the cylindrical can = 32π

Therefore,

volume of the soup in the cylindrical can = 32 × 3.14

volume of the soup in the cylindrical can = 100.48 inches³

learn more on volume here:brainly.com/question/23207959

#SPJ1

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Let X be the random variable for the number of marks a given student receives on the exam.

10% of students obtain more than 75 marks, so

P(X>75)=P\left(\dfrac{X-\mu}\sigma>\dfrac{75-\mu}\sigma\right)=P(Z>z_1)=0.10

where Z follows a standard normal distribution. The critical value for an upper-tail probability of 10% is

P(Z>z_1)=1-F_Z(z_1)=0.10\implies z_1=F_Z^{-1}(0.90)

where F_Z(z)=P(Z\le z) denotes the CDF of Z, and F_Z^{-1} denotes the inverse CDF. We have

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P(X

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\dfrac{75-\mu}\sigma\approx1.2816\implies75\approx\mu+1.2816\sigma

\dfrac{40-\mu}\sigma\approx-0.8416\implies40\approx\mu-0.8416\sigma

and we find

\mu\approx53.8739,\sigma\approx16.4848

3 0
4 years ago
The figures are similar. Find x.
DaniilM [7]

Answer:

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2 years ago
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<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

<em>Find points from graph.</em>

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The population of a town is decreasing at a rate of 3.2% per year. In 2015, there were 14,250 people. What is the first year tha
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The answer is D
you would set up an equation like this
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4 0
2 years ago
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