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stepladder [879]
2 years ago
11

Distance between 1,-4and 7,-4 on a coordinate grid

Mathematics
1 answer:
MAXImum [283]2 years ago
6 0

Answer:

6 units.

Step-by-step explanation:

Distance = √ [(7 - 1)^2 + (-4-(-4))^2]

= √(36 + 0)

= 6 units.

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There are 25 kids in a class, and the number of boys is 2/3 of the number of girls. How many boys and how many girls are in this
Ksju [112]
25 kids in all
2xboys:3x girls
 
so the equation would be 
2x+3x=25
solve,
5x=25
/5           /5
x=5
2x=10
3x=15


10 boys and 15 girls



3 0
3 years ago
A method for finding the volume of any solid for which cross sections by parallel planes have equal area is called
lapo4ka [179]
The appropriate response is Caliveire's <span>Principle</span> It is a technique, with the recipe given beneath, of finding the volume of any strong for which cross-segments by parallel planes have measured up to ranges. This incorporates, yet is not constrained to, chambers and crystals.
7 0
3 years ago
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Which of the following number sentences is true?<br> A -9=9<br> B-9=-(9)<br> C 9=(-9)<br> D 9=-(-9)
kondaur [170]

Answer:

A and D are the true number sentences

3 0
2 years ago
How did I get a 2 here (simplifying ratios)
PilotLPTM [1.2K]

Answer:

\frac{2x {}^{2} + 14x + 24 }{4 {x}^{2} + 4x - 48 }  =  \frac{x + 4}{2(x - 2)}

Step-by-step explanation:

Please see attached picture for full solution.

4 0
3 years ago
A 4 metre ladder is placed against a vertical wall.
Black_prince [1.1K]

Answer:

Original position: base is 1.5 meters away from the wall and the vertical distance from the top end to the ground let it be y and length of the ladder be L.

Step-by-step explanation:

By pythagorean theorem, L^2=y^2+(1.5)^2=y^2+2.25 Eq1.

Final position: base is 2 meters away, and the vertical distance from top end to the ground is y - 0.25 because it falls down the wall 0.25 meters and length of the ladder is also L.

By pythagorean theorem, L^2=(y -0.25)^2+(2)^2=y^2–0.5y+ 0.0625+4=y^2–0.5y+4.0625 Eq 2.

Equating both Eq 1 and Eq 2: y^2+2.25=y^2–0.5y+4.0625

y^2-y^2+0.5y+2.25–4.0625=0

0.5y- 1.8125=0

0.5y=1.8125

y=1.8125/0.5= 3.625

Using Eq 1: L^2=(3.625)^2+2.25=15.390625, L=(15.390625)^1/2= 3.92 meters length of ladder

Using Eq 2: L^2=(3.625)^2–0.5(3.625)+4.0625

L^2=13.140625–0.90625+4.0615=15.390625

L= (15.390625)^1/2= 3.92 meters length of ladder

<em>hope it helps...</em>

<em>correct me if I'm wrong...</em>

4 0
3 years ago
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