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3 years ago

35.) The temperature of dry ice is -109.3°F.

Mathematics

1 answer:

kari74 [83]3 years ago

4 0

Hello there!

You're given the value of -109.3°F, and you are told that is 184.9°F less than the outside temperature. To find the outside temperature, add the difference to the temperature of dry ice.

-109.3°F + 184.9°F =75.6°F

So, the outside temperature is 75.6°F. I hope this was helpful, have a great rest of your day!

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Answer:

7.701

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3 years ago

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The elevation of city A is 80 feet below sea level; the elevation of city C is 16 feet below sea level. The elevation of city D

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Prepare a perpetual inventory record, using the FIFO inventory costing method, and determine the company's cost of goods sol

krek1111 [17]

Answer:

The First-In, First-Out (FIFO) inventory costing method assumes that the inventory items ordered first are the first ones sold.

Step-by-step explanation:

The First-In, First-Out inventory costing method assumes that the inventory items ordered first are the first sold. This is ideal for goods that are highly perishable, for example fresh milk. Since no figures or dates are given, we will assume that the month is March 2019 and use any figures to make the example.

Date Item Quantity of stock Cost Price

01 Opening stock bought on Feb 28 10 100

05 Sale of 5 goods (cost is $10 each) (5) 50

15 Purchase of stock (20 goods at $20 each) 20 400

25 Sale of 15 goods (15) 250

(5 at $10 each & 10 at $20 each)

31 Closing Stock 10 200

(20 goods bought on 15th - 10 goods sold on 25th)

The quantity on hand at the end of the month is 10 units.

Total cost of goods on hand at end of the month = 10 units * $20 = 200.

Total cost of goods purchased during the month = $20 * 20 units = $400

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4 years ago

Can anyone teach mee.....................

andrew11 [14]

Answer:

(i) The name of the part of the circle, OQ is a radius

(ii) The radius of the sector QOR is 21 cm

Step-by-step explanation:

The given figure is a sector of the circle O

∵ Any sector of a circle formed from 2 radii and an arc

∴ OQ is a radius

(i) The name of the part of the circle, OQ is a radius

The rule of the length of an arc of a circle is L = $\frac{\alpha }{360}$ × 2 π r, where

α is the angle of the sector

r is the radius of the circle

∵ The length of the arc QR is 22 cm

∴ L = 22

∵ The measure of the angle of the arc is 60°

∴ α = 60°

∵ π = $\frac{22}{7}$

→ Substitute them in the rule above

∵ 22 = $\frac{60}{360}$ × 2 × $\frac{22}{7}$ × r

∴ 22 = $\frac{22}{21}$ r

→ Divide both sides by $\frac{22}{21}$

∴ 21 = r

(ii) The radius of the sector QOR is 21 cm

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3 years ago

Ray has found that his new car gets 31 miles per gallon on the highwayand 26 miles per gallon in the city. He recently drove 285

Mkey [24]

Answer:

$Highway = 155\ miles$

$City = 130\ miles$

Step-by-step explanation:

Given

$Highway = 31mi/gallon$

$City = 26mi/gallon$

$Total\ Miles = 285$

$Total\ Gallons = 10$

Required

Determine the number of miles driven on the highway and on the city

Represent the gallons used on highway with h and on city with c.

So, we have:

$c + h = 10$ ---- gallons used

and

$31h + 26c = 285$ --- distance travelled

In the first equation, make c the subject

$c = 10 - h$

Substitute 10 - h for c in the second equation

$31h + 26c = 285$

$31h + 26(10 - h) = 285$

Open bracket

$31h + 260 - 26h = 285$

Collect like terms

$31h - 26h = 285 - 260$

$5h = 25$

Make h the subject

$h = \frac{25}{5}$

$h = 5$

Substitute 5 for h in $c = 10 - h$

$c = 10 - 5$

$c = 5$

If on the highway, he travels 31 miles per gallon, then his distance on the highway is:

$Highway = 31 * 5$

$Highway = 155\ miles$

If in the highway, he travels 26 miles per gallon, then his distance on the highway is:

$City = 26 * 5$

$City = 130\ miles$

8 0

3 years ago