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MariettaO [177]
3 years ago
9

35.) The temperature of dry ice is -109.3°F.

Mathematics
1 answer:
kari74 [83]3 years ago
4 0

Hello there!

You're given the value of -109.3°F, and you are told that is 184.9°F less than the outside temperature. To find the outside temperature, add the difference to the temperature of dry ice.

-109.3°F + 184.9°F =75.6°F

So, the outside temperature is 75.6°F. I hope this was helpful, have a great rest of your day!

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<h3>Answer: 24/25</h3>

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Explanation:

Sine is given to be negative, and so is tangent. This only happens in quadrant Q4

Recall that y = sin(theta), so if sin(theta) < 0, then we're below the x axis.

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Draw a right triangle as shown below in the attached image. We have AC = 25 and BC = 7. Use the pythagorean theorem to find that AB = 24

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a^2+b^2 = c^2

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As an alternative, you could use the trig identity

sin^2(x) + cos^2(x) = 1

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sin^2(x) + cos^2(x) = 1

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cos(x) = sqrt(576)/sqrt(625)

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This is effectively a rephrasing of the previous section since the pythagorean trig identity is more or less the pythagorean theorem (just in a trig form)

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