Answer:
Witch point is best represented by the ordered pair (2,-5.5)
Step-by-step explanation:
40% of 250 is 100, meaning that if 40% of 250 students are girls, then there are 150 boys!!
250 divided by 10 is 25, so you multiply 25 by 4 to get 40%!!
Answer:
She can chose 2 books from 8 books in 28 different way.
Step-by-step explanation:
In the given scenario the member has to chose 2 books from a group of 8 books. The order of choosing books does not matter. For example if the books are A,B,C,D,E,F,G and H, and the member picks books A and B or books B and A, she is picking up the same books. This means order of selection does not matter here, so this is a problem of combinations.
We have to form combination of 8 books taken 2 at a time i.e. 8C2
The general formula of combination is:
![nCr=\frac{n!}{r!(n-r)!}](https://tex.z-dn.net/?f=nCr%3D%5Cfrac%7Bn%21%7D%7Br%21%28n-r%29%21%7D)
Using the values of n=8 and r=2, we get:
![8C2=\frac{8!}{2!(8-2)!}=28](https://tex.z-dn.net/?f=8C2%3D%5Cfrac%7B8%21%7D%7B2%21%288-2%29%21%7D%3D28)
This means, she can chose 2 books from 8 books in 28 different ways.
Answer:
3
Step-by-step explanation:
as a person who answers in the mathematics session
i will tell you that the answer is 3
Answer:
Length = 18.099 ft
Width = 11.049 ft
Step-by-step explanation:
let the length of the field be x ft
and the width be y ft
as per the condition given in problem
x=2y-4 -----------(A)
Also the area is given as 200 sqft
Hence
xy=200
Hence from A we get
y(2y-4)=200
taking 2 as GCF out
2y(y-2)=200
Dividing both sides by 2 we get
![y(y-2)=100](https://tex.z-dn.net/?f=y%28y-2%29%3D100)
![y^2-2y=100](https://tex.z-dn.net/?f=y%5E2-2y%3D100)
subtracting 100 from both sides
![y^2-2y-100=0](https://tex.z-dn.net/?f=y%5E2-2y-100%3D0)
Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form
![ax^2+bx+c=0](https://tex.z-dn.net/?f=ax%5E2%2Bbx%2Bc%3D0)
Here in our case
a=1
b=-1
c=-100
Putting those values in the formula and solving them for y
![y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B-%28-2%29%2B%5Csqrt%7B%28-2%29%5E2-4%20%5Ctimes%20%28-1%29%20%5Ctimes%20100%7D%7D%7B2%20%5Ctime%201%7D)
![y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B-%28-2%29-%5Csqrt%7B%28-2%29%5E2-4%20%5Ctimes%20%28-1%29%20%5Ctimes%20100%7D%7D%7B2%20%5Ctime%201%7D)
Solving first
![y=\frac{2+\sqrt{4+400}{2}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B2%2B%5Csqrt%7B4%2B400%7D%7B2%7D)
![y=\frac{2+\sqrt{404}{2}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B2%2B%5Csqrt%7B404%7D%7B2%7D)
![y=\frac{2+20.099}{2}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B2%2B20.099%7D%7B2%7D)
![y=\frac{22.099}{2}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B22.099%7D%7B2%7D)
![y=11.049](https://tex.z-dn.net/?f=y%3D11.049)
Solving second one
![y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B-%28-2%29-%5Csqrt%7B%28-2%29%5E2-4%20%5Ctimes%20%28-1%29%20%5Ctimes%20100%7D%7D%7B2%20%5Ctime%201%7D)
![y=\frac{2-\sqrt{4+400}{2}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B2-%5Csqrt%7B4%2B400%7D%7B2%7D)
![y=\frac{2-\sqrt{404}{2}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B2-%5Csqrt%7B404%7D%7B2%7D)
![y=\frac{2-20.099}{2}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B2-20.099%7D%7B2%7D)
![y=\frac{-18.99}{2}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B-18.99%7D%7B2%7D)
![y=-9.045](https://tex.z-dn.net/?f=y%3D-9.045)
Which is wrong as the width can not be in negative
Our width of the field is
y=11.099
Hence the length will be
x=2y-4
x=2(11.049)-4
x=22.099-4
x=18.099
Hence our length x and width y :
Length = 18.099 ft
Width = 11.049 ft