How loud a sound is depending on how far away you are PLEASE !!!!!help asap

How would 7/2 be written as a complex number

ValentinkaMS [17]

Answer:

We could rewrite 7/2 as 7a + 2

Step-by-step explanation:

Complex numbers is when real numbers [i.e: 1, 1/2, 200, 5/7, etc..) and an imaginary numbers [numbers that give a negative result when squared] are combine together.

3 0

4 years ago

PLEASE HELP ME ASAP

LiRa [457]

Answer: Distributive hope this helps.

Step-by-step explanation:

5 0

3 years ago

4th grade math question Joey walk 333 ft how many yards did Joey walk? At 5 yds vs 15 ft

icang [17]

111 yards

Explanation

Step 1

to solve this we need to know the equivalence

$\begin{gathered} 3\text{ ft= 1 yd} \\ 3\text{ ft}\leftrightarrow1\text{ yd} \end{gathered}$

Now, we can apply a rule of three

let x represents the number of yards in 333 ft, so

so

$\begin{gathered} if \\ 3\text{ ft}\rightarrow\text{ 1 yd} \\ \text{then} \\ 33\text{ ft}\rightarrow x \end{gathered}$

as the ratio is the same, we have a proportion

$\begin{gathered} \frac{3\text{ ft}}{1\text{ yd}}=\frac{33\text{ ft}}{x\text{ yd}} \\ \frac{3}{1}=\frac{33}{x} \end{gathered}$

Step 2

now, solve for x

$\begin{gathered} \frac{3}{1}=\frac{333}{x} \\ \text{cross multiply} \\ 3\cdot x=333\cdot1 \\ 3x=333 \\ \text{divide both } \\ \frac{3x}{3}=\frac{333}{3} \\ x=111 \end{gathered}$

so, the answer is 111 yards

I hope this helps you

8 0

1 year ago

I need to simplify the circled questions and explain how I got my answers.

postnew [5]

#7 2^3÷2(3+2) 2^2×(3+2) 4×5 20

6 0

3 years ago

Read 2 more answers

a band of 45 ewoks crash-landed in the forest last night. this sounds like a small problem, but the population will grow at the

kogti [31]

Given Information:

Starting population = P₀ = 45

rate of growth = 22%

Required Information:

Population every five years from this year to the year 2050 = ?

Answer:

$Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\$

Step-by-step explanation:

The population growth can be modeled as an exponential function,

$P(t) = P_0e^{rt}$

Where P₀ is the starting population, r is the rate of growth of the population and t is the time in years.

We are given that starting population of 45 and growth rate of 22%

$P(t) = 45e^{0.22t}$

Assuming that the starting year is 2020,

$Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\$

Therefore, the starting population of ewoks was 45 in 2020 and increased to 33,079 by 2050 in a time span of 30 years.

8 0

3 years ago