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1 year ago

in an inelastic collision, kinetic energy is not conserved. where does it go? (select all that apply)

1 answer:

5 0

In an elastic collision, although total energy of a system is always conserved, kinetic energy carried by the moving objects is not always conserved. It is lost in the environment.

In an inelastic collision, energy is lost in the environment and transferred into other forms such as heat. When total kinetic energy is not conserved, then that collision is called as an inelastic collision.

Although momentum is conserved in inelastic collisions but it is difficult to track the kinetic energy through the collision since some of it is converted into other forms of energy.

An inelastic collision in a ballistic pendulum. Another example of an inelastic collision is a ballistic pendulum or dropped ball of clay. A dropped ball of clay doesn't rebound instead it loses kinetic energy through deformation on hitting the ground and changes shape.

To know more about inelastic collisions, refer

brainly.com/question/24434011

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The posted speed limit on the road heading from your house to school is45 mi/h, which is about 20 m/s. If you live 8 km (8,000 m

zaharov [31]

Answer:

20.

Explanation:

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3 years ago

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About ________ percent of wais scores fall between 70 and 130.

stiv31 [10]

It is about 95%. The Wechsler Adult Intelligence Scale-IV is an IQ test that is given by therapists and measures worldwide scholarly working. It incorporates both verbal and nonverbal parts. The normal score for all tests and subtests is 100; therefore, a score of more than 100 is better than expected and beneath 100 is underneath normal.

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4 years ago

What is the equation for measuring the change in thermal energy?

Daniel [21]

Answer:

Explanation: I think...

Thermal Energy formula Q = mcΔT

Q = Thermal Energy(J)

m = Mass(kg)

c = Specific Heat(J/kg°C)

ΔT = Change in Temperature(°C)

you have to write the equation based on what you are working on

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3 years ago

A 250 GeV beam of protons is fired over a distance of 1 km. If the initial size of the wave packet is 1 mm, find its final size

Margarita [4]

Answer:

The final size is approximately equal to the initial size due to a very small relative increase of $1.055\times 10^{- 7}$ in its size

Solution:

As per the question:

The energy of the proton beam, E = 250 GeV = $250\times 10^{9}\times 1.6\times 10^{- 19} = 4\times 10^{- 8} J$

Distance covered by photon, d = 1 km = 1000 m

Mass of proton, $m_{p} = 1.67\times 10^{- 27} kg$

The initial size of the wave packet, $\Delta t_{o} = 1 mm = 1\times 10^{- 3} m$

Now,

This is relativistic in nature

The rest mass energy associated with the proton is given by:

$E = m_{p}c^{2}$

$E = 1.67\times 10^{- 27}\times (3\times 10^{8})^{2} = 1.503\times 10^{- 10} J$

This energy of proton is $\simeq 250 GeV$

Thus the speed of the proton, v $\simeq c$

Now, the time taken to cover 1 km = 1000 m of the distance:

T = $\frac{1000}{v}$

T = $\frac{1000}{c} = \frac{1000}{3\times 10^{8}} = 3.34\times 10^{- 6} s$

Now, in accordance to the dispersion factor;

$\frac{\delta t_{o}}{\Delta t_{o}} = \frac{ht_{o}}{2\pi m_{p}\Delta t_{o}^{2}}$

$\frac{\delta t_{o}}{\Delta t_{o}} = \frac{6.626\times 10^{- 34}\times 3.34\times 10^{- 6}}{2\pi 1.67\times 10^{- 27}\times (10^{- 3})^{2} = 1.055\times 10^{- 7}$

Thus the increase in wave packet's width is relatively quite small.

Hence, we can say that:

$\Delta t_{o} = \Delta t$

where

$\Delta t$ = final width

3 0

3 years ago

. (a) How long can you play tennis on the 800 kJ (about 200 kcal) of energy in a candy bar? (b) Does this seem like a long time?

galina1969 [7]

(a). The power of the candy bar is,

$P=440\text{ W}$

The time taken to play on 800 kJ energy of the candy bar is,

$t=\frac{E}{P}$

where E is the energy.

Substituting the known values,

$\begin{gathered} t=\frac{800\times10^3}{440} \\ t=1.818\times10^3\text{ s} \\ t=1818\text{ seconds} \end{gathered}$

As 1 minute is equal to 60 seconds,

Thus,

$\begin{gathered} t=1818\text{ seconds} \\ t=\frac{1818}{60} \\ t=30.3\text{ min} \end{gathered}$

Thus, the time taken to play tennis on the 800 kJ energy is 30.3 minutes.

(b). By doing the exercise, the process of digestion of food inside our body increases. Thus, the exercise does not helps us to burn the calories. But it helps us to diggest the heavy meal like candy bar easily.

The time taken to digest the canndy bar or to utilise its energy is large because it takes a lot of time to burn small amount of food and make it digest quickly.

8 0

1 year ago