Ask question

Ask question

All categories

3 years ago

7

a closed tank is partially filled with glycerin. if the air pressure in the tank is 6 lb/in.2 and the depth of glycerin is 10 ft

, what is the pressure in lb/ft2 at the bottom of the tank

1 answer:

KATRIN_1 [288]3 years ago

4 0

Answer:

<u><em>note:</em></u>

<u><em>solution is attached due to error in mathematical equation. please find the attachment</em></u>

You might be interested in

The power output of a laser is measured by its wattage, the number of joules of energy it radiates per second (1 W = 1 J s-1). A

viva [34]

Explanation:

It is given that,

Wavelength of red light, $\lambda=676.4\ nm=676.4\times 10^{-9}\ m$

Power of the laser, $P=300\ mW=0.3\ W$

(a) The energy carried by each photon is given by :

$E=\dfrac{hc}{\lambda}$

$E=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{676.4\times 10^{-9}}$

$E=2.94\times 10^{-19}\ J$

(b) Let n is the number of photons emitted by the laser per second. It can be calculated as :

$n=\dfrac{Power}{Energy\ of\ one\ photon}$

$n=\dfrac{0.3}{2.94\times 10^{-19}}$

$n=1.02\times 10^{18}\ photon/s$

Hence, this is the required solution.

7 0

3 years ago

S a Mountain lion a producer consumer or decomposer

larisa86 [58]

A mountain lion is a consumer it its prey , a decomposer is like a worm
Hope this helps! :)

3 0

3 years ago

Read 2 more answers

a runner makes one lap around a 200m track in 25s, what is the runners (a) average speed and (b) average velocity

TEA [102]

hiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii

5 0

3 years ago

A 0.015 kg marble sliding to the right at 22.5 cm/s on a frictionless surface makes an elastic head-on collision with a 0.015 kg

slava [35]

Answer:

Explanation:

mass of first marble $m_1=m=0.015\ kg$

Initial velocity of the first marble $u_1=22.5\ m/s$

considering right side as positive

Mass of second marble

$m_2=m=0.015\ kg\\u_2=-18\ cm/s$

After collision first marble moves to the left with a velocity of 18 cm/s

i.e. $v_1=-18\ cm/s$

considering $v_2$ be the velocity of second marble after collision

The Coefficient of restitution is 1 for an elastic collision

$e=\frac{v_2-v_1}{u_1-u_2}$

Putting values

$1=\frac{v_2-(-18)}{22.5-(-18)}\\22.5+18=v_2+18\\v_2=22.5\ m/s$

So, the velocity of the second marble is 22.5 m/s to the right after the collision

(b)Initial kinetic energy = $0.5\times 0.015\times (22.5\times 10^{-2})^2+0.5\times 0.015\times (18\times 10^{-2})^2=6.22\times 10^{-4}\ J$

Final kinetic energy=

$0.5\times 0.015\times (18\times 10^{-2})^2+0.5\times 0.015\times (22.5\times 10^{-2})^2=6.22\times 10^{-4}\ J$

6 0

3 years ago

An object of mass 0.50 kg is transported to the surface of Planet X where the object's weight is measured to be 20 N. The radius

vovangra [49]

Explanation:

The free fall acceleration is:

F = ma

20 N = (0.50 kg) a

a = 40 m/s²

The mass of Planet X is:

F = GMm / r²

20 N = (6.67×10⁻¹¹ Nm²/kg²) M (0.50 kg) / (4.0×10⁶ m)²

M = 9.6×10²⁴ kg

5 0

3 years ago