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miv72 [106K]
2 years ago
15

((5x-16) cubed -4)cubed = 216,000X = _________

Mathematics
1 answer:
Lemur [1.5K]2 years ago
4 0

Given the equation:

((5x-16)^3-4)^3=216000

Applying the exponent laws:

\begin{gathered} \sqrt[3]{((5x-16)^3-4)^3}=\sqrt[3]{216000} \\ (5x-16)^3-4=60 \end{gathered}

Simplify:

\begin{gathered} (5x-16)^3-4+4=60+4 \\ (5x-16)^3=64 \end{gathered}

Applying the exponent laws:

\begin{gathered} \sqrt[3]{(5x-16)^3}=\sqrt[3]{64} \\ Simplify \\ 5x-16=4 \\ 5x-16+16=4+16 \\ 5x=20 \\ \frac{5x}{5}=\frac{20}{5} \\ x=4 \end{gathered}

Answer: x = 4

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6(m +2 + 7m <br> Please help please help
NISA [10]

Answer:

i think that is 2m + m14

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
1.2,3,7.5,18.75, which formula can be used to describe the sequence
elena-14-01-66 [18.8K]

Answer:

a_{n}=1.2 \times(2.5)^{n-1}

Step-by-step explanation:

If we observe the given sequence, we find that the ratio of two consecutive terms is the same. i.e.

\frac{3}{1.2}=2.5\\\\\frac{7.5}{3}=2.5\\\\ \frac{18.75}{7.5}=2.5

Such a sequence in which the ratio of consecutive terms remain the same is know as Geometric Sequence. Following formula is used to represent a Geometric Sequence:

a_{n}=a_{1}\times(r)^{n-1}

Here:

a_{n} is the general term. Using the value of n =1,2,3 ... will give us the term of the sequence.

a_{1} is the first term which is 1.2 in this case.

r represents the common ratio which is 2.5.

Using these values we get:

a_{n}=1.2 \times(2.5)^{n-1}

This formula can be used to represent the given sequence.

3 0
4 years ago
Find the shaded area
azamat

Answer:

101 degrees

Step-by-step explanation:

the sum of all angles in a triangle is always 180 degrees.

the other not-shaded angle in the lower triangle is also 42 degrees.

the shaded angle is therefore

180 - 37 - 42 = 101 degrees

4 0
4 years ago
In a certain game, a player can solve easy or hard puzzles. A player earns 30 points for solving an easy puzzle and 60 points fo
Karolina [17]

This is a system of equations. We can solve it by recognizing the two linear equalities we've given to solve this equation.

First, let's start off by recognizing two variables: x and y. x will be our number of hard puzzles, and y will be our number of easy puzzles. We're given that the number of hard puzzles and easy puzzles sum to 50, so we can rewrite that as:

x+y=50

Next, we're given that the sum of the points gained from the hard puzzles (60x), and the number of points gained from the easy puzzles (30y), sum to 1950. We can rewrite that as:

60x+30y=1950

Now, we have our two linear equations, and we must solve for the hard puzzles, so x. Solving for the hard puzzles means eliminating the easy puzzles from our systems, so we can multiply our first equation by 30, and subtract it from the first equation. This is a technique called elimination.

30x+30y=1500 \\ 60x+30y=1950 \\ 30x=450 \implies x=15

Since x=15, Tina has solved 15 hard puzzles.

3 0
3 years ago
Help solve for number 6 please !!<br> :)
Semenov [28]

Answer:

x: {-3, 5}

Step-by-step explanation:

Step 1. Find least common denominator

Step 2. Multiply missing factors on top AND bottom

Step 3. Combine like terms

Step 4. Simplify (get rid of denominator)

Step 5. Solve for x

\frac{x}{x-5} +\frac{3}{x+2} =\frac{7x}{x^2-3x-10}            LCD = x^2-3x-10   OR  (x-5)(x+2)

\frac{x}{x-5}(\frac{x+2}{x+2})  +\frac{3}{x+2}(\frac{x-5}{x-5})  =\frac{7x}{x^2-3x-10}

\frac{x(x+2)}{(x-5)(x+2)} +\frac{3(x-5)}{(x+2)(x-5)} =\frac{7x}{(x-5)(x+2)}

\frac{x(x+2)+3(x-5)}{(x-5)(x+2)} =\frac{7x}{(x-5)(x+2)}

\frac{x^2+2x+3x-15}{(x-5)(x+2)} =\frac{7x}{(x-5)(x+2)}

\frac{x^2+5x-15}{(x-5)(x+2)} =\frac{7x}{(x-5)(x+2)}

x^2+5x-15=7x

x^2-2x-15

(x-5)(x+3)

<u>x = -3, 5</u>

8 0
3 years ago
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