Elimination:
7x - 3y = 20
5x + 3y = 16
(add)
12x = 36
÷ 12
x = 3
(5 × 3) + 3y = 16
15 + 3y = 16
- 15
3y = 1
÷ 3
y = 1/3
Substitution:
5x + 3y = 16
- 3y
5x = 16 - 3y
÷ 5
x = 3.2 - 0.6y
5(3.2 - 0.6y) + 3y = 16
16 - 3y + 3y = 16
16 = 16
- 16
6y = 0
÷ 6
y = 0
Sorry the substitution messed up for some reason, I'll fix it after I've answered the other question
Answer: 129.33 g
Step-by-step explanation:



On the y-axis.
Hope this helps!!
Let x be the yard length, then if <span>the length of the yard is 10 feet more than 2 times the width, the length of the yard is 2x+10. The perimeter is 2 lengths + 2 widths, so P=2x+2(2x+10) .
</span>
Since Sally <span>needs 56 feet of fencing to do the job, P=56 ft. and
</span>
<span>2x+2(2x+10)=56,
</span><span>
</span><span>2x+4x+20=56,
</span><span>
</span><span>6x=56-20,
</span><span>
</span><span>6x=36,
</span><span>
</span><span>x=6 ft. and 2x+10=12+10=22 ft.
</span><span>
</span><span>Answer: The length of the yard is 22 feet</span>