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1 year ago

I need help with a problem

Mathematics

1 answer:

patriot [66]1 year ago

5 0

Answer : (5w, -4w)

We are given a pentagon KLMNO with different vertices

K = ( -5, 2)

L = ( 0, 5)

M = ( 5, 2)

N = (5, -4)

O = (-5, -4)

Dilation is defined as the proportional strectch or shrink of an image on the coordinate plane base on the scale factor.

Since, coordinate N is dilated by a scale factor of w

Therefore, the two points is multiply by the scale factor w

The dilated coordinate becomes, (5 x w , -4 x w)

(5w, -4w)

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John earns a 3% commission for every car he sells. Today he sold a car for $13,600. How much commission did he receive? (To find

Vanyuwa [196]

Answer:

$408

Step-by-step explanation:

What we know:

John earns a 3% commission for every car he sells.

He sold a car today for $13,600.

Multiply 3/100 by 13,600 to get your answer.

3/100 * 13600

40800/100

$408 in commission

8 0

3 years ago

Read 2 more answers

Solve for d. 41 =12d-7

soldier1979 [14.2K]

Answer:

d=4

Step-by-step explanation:

just trust me

(Add 7 both sides - 48 = 12d,

divide both sides by 12 - d = 4)

4 0

3 years ago

Please solve the problem

jek_recluse [69]

Treat the matrices on the right side of each equation like you would a constant.

Let 2X + Y = A and 3X - 4Y = B.

Then you can eliminate Y by taking the sum

4A + B = 4 (2X + Y) + (3X - 4Y) = 11X

==> X = (4A + B)/11

Similarly, you can eliminate X by using

-3A + 2B = -3 (2X + Y) + 2 (3X - 4Y) = -11Y

==> Y = (3A - 2B)/11

It follows that

$X=\dfrac4{11}\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\dfrac1{11}\begin{bmatrix}7&-10\\-7&11\end{bmatrix} \\\\ X=\dfrac1{11}\left(4\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\left(\begin{bmatrix}48&-12\\40&88\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\begin{bmatrix}55&-22\\33&99\end{bmatrix} \\\\ X=\begin{bmatrix}5&-2\\3&9\end{bmatrix}$

Similarly, you would find

$Y=\begin{bmatrix}2&1\\4&4\end{bmatrix}$

You can solve the second system in the same fashion. You would end up with

$P=\begin{bmatrix}2&-3\\0&1\end{bmatrix} \text{ and } Q=\begin{bmatrix}1&2\\3&-1\end{bmatrix}$

3 0

3 years ago

Solve the equation. |x + 5| = 9 {–4, 14} {–14, 4} {4, 14} {–14, –4}

inna [77]

Answer:

{-14, 4}

Step-by-step explanation:

the absolute value function only makes sure that the result always has a positive sign.

so, (x + 5) must be either +9 or -9 to make the original equation true. the absolute value would turn both into +9.

so,

x + 5 = 9

x = 4

and

x + 5 = -9

x = -14

that gives us the correct set of solutions as indicated above.

6 0

3 years ago

PLEASE help!!!!!!!!!!!!!!!!!!!!!!!!!!!

Luba_88 [7]

Answer: 11

Step-by-step explanation: 5x-15= 3x+7

Combine like terms: 2x= 7+15

Add = 2x= 22

Divide: equals 11

4 0

3 years ago