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Mamont248 [21]
1 year ago
10

The table shows how many books the students in Bergdalsskolan list during the summer. There were 48 students who list 4 books. a

) How many students had read 1 book? b) What percentage more read 2 books than 4 books?

Mathematics
1 answer:
Juliette [100K]1 year ago
8 0

Step 1:

First, find the total number of students.

Let the total number of students = m

Step 2:

Find the total number of students using the percentage of 4 books.

48 students listed 4 books with a percentage of 16%

\begin{gathered} 48\text{ = 16\% of m} \\ 48\text{ = }\frac{16}{100}\text{   }\times\text{  m} \\ 48\text{ = }\frac{16m}{100} \\ \text{Cross multiply} \\ 16m\text{ = 48  }\times\text{  100} \\ 16m\text{ = 4800} \\ \text{m = }\frac{4800}{16} \\ \text{m = 300} \end{gathered}

Hence, there are 300 students.

a)

\begin{gathered} \text{Number of students that had 1 book = 24\% of 300} \\ =\text{ }\frac{24}{100}\text{  }\times\text{  300} \\ =\text{ }\frac{7200}{100} \\ =\text{ 72  students} \end{gathered}

72 students had 1 book.

b) What percentage more read 2 books than 4 books?

percentage that read 2 books = 36%

percentage that read 4 books = 16%

36 - 16 = 20%

There are 20% students that read 2 books than 4 books.

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(Note: Division of big numbers should be done by simplification, although not shown here.)

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2 years ago
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Answer:

The equation is y= 0,65 x

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The line should be in the first quadrant because the first quadrant allows you to represent a situation in which the dependent variable (y) and the independent variable (x) are both positive. This is the case in this exercise, because both prices, the one without discount (x) and the one with discount (y) are necessary positive (you can not pay a negative price!).

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The price without discount (or without the coupon) is x.

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