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zhenek [66]
3 years ago
12

Find all solutions 2cos(theta)+1=0 write in radians in terms of pi.

Mathematics
1 answer:
Orlov [11]3 years ago
7 0
<span>As we know
cos theta-1= 0 
 cos theta = 1
  Now Look at a graph of the cosine function
, and you will observe that cos theta = 1
 at the points X = 0, and X = 2pi
hope it helps</span>
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Find the product of the greatest common divisor and the least common multiple of $100$ and $120.$
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Peter left his home in Chicago and drove to a town a few hours away. On the way there, he drove 40 mph due to traffic, but on th
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4 0
3 years ago
During a scuba dive, Lainey descended to a point 19 feet below the ocean surface. She continued her descent at a rate of 25 feet
Leno4ka [110]

Answer:

25t+19\leq 144

t\leq5

The number of minutes she can continue to descend if she does not want to reach a point more than 144 feet below the ocean surface is <u>at most 5 minutes.</u>

Step-by-step explanation:

Given:

Initial depth of the scuba dive = 19 ft

Rate of descent = 25 ft/min

Maximum depth to be reached = 144 ft

Now, after 't' minutes, the depth reached by the scuba dive is equal to the sum of the initial depth and the depth covered in 't' minutes moving at the given rate.

Framing in equation form, we get:

Total depth = Initial Depth + Rate of descent × Time

Total depth = 19+25t

Now, as per question, the total depth should not be more than 144 feet. So,

\textrm{Total depth}\leq 144\ ft\\\\19+25t\leq 144\\\\or\ 25t+19\leq 144

Solving the above inequality for time 't', we get:

25t+19\leq 144\\\\25t\leq 144-19\\\\25t\leq 125\\\\t\leq \frac{125}{25}\\\\t\leq 5\ min

Therefore, the number of minutes she can continue to descend if she does not want to reach a point more than 144 feet below the ocean surface is at most 5 minutes.

7 0
3 years ago
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