Find all solutions 2cos(theta)+1=0 write in radians in terms of pi.

1 answer:

7 0

As we know
cos theta-1= 0
cos theta = 1
Now Look at a graph of the cosine function
, and you will observe that cos theta = 1
at the points X = 0, and X = 2pi
hope it helps

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would some one understand me please and helps me with this one I have been try to solve it for a week.

Arte-miy333 [17]

Answer:

The value of x in all the cases is $\frac{22}{4}$ .

Step-by-step explanation:

The given equation is:

$4x + 10 = 32$

a. Add 4 on both the sides. The equation becomes $4x + 14 = 36$

The operation of addition (or subtraction) done on both the sides of the equation will not alter the value. They will still be equal. However, adding a non - zero term to only one side of the equation will result in the equation becoming unequal.

b. Equivalent Equations are those equations which have the same roots or solutions. Note that, the equations $4x + 10 = 32$ and $4x + 14 = 36$ have the same solution. Then these equations can be named 'equivalent equations'.

c. Subtraction:

Subtract any number from both the sides of the equation, say, 5.

$\implies 4x + 5 = 27$ . The solution is still not altered.

Multiplication:

Multiply through by 2. We get: $8x + 20 = 64$ . The value of x is still the same.

Division:

Divide through out by -2. The solution is unaltered.

Note that operations of Multiplication and Division are to be done by non -zero numbers. Otherwise it would be altered.

3 0

2 years ago

a. Find symmetric equations for the line that passes through the point (4, −4, 8) and is parallel to the vector −1, 4, −3b. Find

daser333 [38]

The line has equation

$\vec r(t)=(4,-4,8)+(-1,4,-3)t$

where $t$ is any real number. $(-1,4,-3)t$ is the line containing all scalar multiples of the vector (-1, 4, -3); we add (4, -4, 8) to shift the line so that it passes through this point while remaining parallel to the the line.