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Nostrana [21]
10 months ago
9

the distance between City a and City b is 200 mi. on a certain wall map this is represented by the length of 1.7 ft. On the map

how many feet would there be between City c and City d two cities that are actually 400 mi apart?
Mathematics
1 answer:
ruslelena [56]10 months ago
5 0

Given that:

the distance between City a and City b is 200 mi. on a certain wall map this is represented by the length of 1.7 ft.

So:

\begin{gathered} 200\text{ mi=1.7 ft } \\ 1\text{ mi=}\frac{1.7}{200}ft \end{gathered}

between City c and City d two cities that are actually 400 mi apart?:

So for 400 mi.

\begin{gathered} 1\text{ mi=}\frac{1.7}{200}ft \\ 400\text{ mi=400}\times\frac{1.7}{200}ft \\ 400mi=2\times1.7ft \\ 400\text{ mi=3.4ft} \end{gathered}

So 3.4 feet would there be between City c and City d two cities that are actually 400 mi apart

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\sqrt{41}

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Hello!

In order to answer this question, we need to use the distance formula.

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Hello,
Nookie1986 [14]

Answer:

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I will do it the hard (11) waay by completing the square

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