See the picture attached to better understand the problem
we know that
If two secant segments are drawn to a <span>circle </span><span>from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.
</span>so
jl*jk=jn*jm------> jn=jl*jk/jm
we have
<span>jk=8,lk=4 and jm=6
</span>jl=8+4----> 12
jn=jl*jk/jm-----> jn=12*8/6----> jn=16
the answer isjn=16
Answer:
Yes
Step-by-step explanation:
Yes it is a function, because graph is intersecting y - axis only once.
From the function given:
y=x^2-5
this can be written as:
y=x^2+0x-5
writing in vertex form we get:
y=(x-h)^2+k
where: (h,k) is the vertex
y=(x-0)^2-5
thus the vertex is at (0,-5)
the parent function is y=x^2, thus the graph of the parent function is First graph
Assuming your solving for y:
py+7=6y+q
-6y -7 -6y -7
(p-6)y = q-7
divide both sides by p-6
y=(q-7)/(p-6)
Answer:
IT would be 13a to 17b
Step-by-step explanation:
I had this.