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larisa [96]
3 years ago
7

ANSWER PLEASE! Pic attached.

Mathematics
1 answer:
olasank [31]3 years ago
8 0

Ah, Micah, that rat.

The answer is B, I took the test and that was correct.

If you break the equation up into systems, you can see that they intersect at 0.297, which would be the solution to the systems.

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Wellington has $21 to ride bumper cars and play games at the count fair. Suppose the bumper cars cost $3.50. Write and solve an
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Answer: 17.50

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A ladder 10 m long,leans against a vertical wall at an angle of 70° to the ground.if the ladder slips down the wall 4m,find,corr
lina2011 [118]

Answer:

(a) the new angle the ladder makes with the ground is 32.7^o

(b) the ladder slipped back about 5 meters

Step-by-step explanation:

Notice that the ladder doesn't change its length in the process.

So let's start from the initial situation , finding the distance from the ground at which the ladder touches the wall when the angle with the ground is 70^o. Notice that this situation is represented by a right angle triangle with the right angle between the wall and the ground (see attached image), and that we can use the sine function to find the side opposite to the 70 degree angle:

sin(70^o)=\frac{opposite}{hypotenuse} \\sin(70^o)=\frac{h}{10}\\h=10\, sin(70^o) \approx 9.4 \,\,m

therefore 9.4 meters is approximately the height at which the ladder touches the wall initially.

Now, if the tip of the ladder goes down the wall 4 meters, it is now at 9.4 m - 4 m = 5.4 m from the ground. We can therefore use again the sine function to solve for the new angle:

sin(x)=\frac{opposite}{hypotenuse} \\sin(x)=\frac{5.4}{10} \\sin(x)=0.54\\x=arcsin(0.54)\\x= 32.7^o

To answer the second question we need to find the original distance from the wall that the bottom of the ladder was originally, and for that we can use the cosine function:

cos(70^o)=\frac{adjacent}{hypotenuse} \\cos(70^o)=\frac{x}{10}\\x=10\,cos(70^o)\\x\approx 3.4  \,\,m

Now fro the new position of the bottom of the ladder relative to the wall:

cos(32.7^o)=\frac{adjacent}{10} \\adjacent=10\,cos(32.7^o)\\adjacent\approx 8.4\,\,m

then the difference in between those two distances is what we need:

8.4 m - 3.4 m = 5 m

4 0
3 years ago
MODEL HOUSE Baron built a square pyramid block to use as the roof of a model house he was making. The square base had sides of l
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I think the answer is 14, but rounded to the nearest tenth will be 10.......

Step-by-step explanation:

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Fran is training for her first marathon, and she wants to know if there is a significant difference between the mean number of m
Tcecarenko [31]

Answer:Sorry i have no time to read it all bro

Step-by-step explanation:

4 0
3 years ago
Question is in picture! answer asap! will give brainliest!
nataly862011 [7]

Answer:solve for x

-3x+5y=-15

Add -5y to both sides

-3x+5y+-5y=-15+-5y

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Divide both sides by -3

-3x/-3=-5y-15/-3

x= 5/3 y +5

I hope that's help!

Step-by-step explanation: plz give brainlist

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