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DerKrebs [107]
1 year ago
8

Find the solution(s) of the system of equations:

Mathematics
1 answer:
murzikaleks [220]1 year ago
7 0

The solutions are (0, - 6) ,(7, 8)

The given system of equations is expressed as

y = x² - 5x - 6- - - - - - - - - - - - (1)

y = 2x - 6- - - - - - - - - - - (2)

We would apply the method of substitution by substituting equation 2 into equation 1. It becomes

x² - 5x - 6 = 2x - 6

x² - 5x - 6 = 2x - 6

x² - 5x - 2x - 6 + 6 = 0

x² - 7x = 0

x(x - 7) = 0

x = 0 or x - 7 = 0

x = 7 or x = 0

Substituting x = 0 into equation 2, it becomes

y = 2 × 0 - 6

y = - 6

Substituting x = 7 into equation 2, it becomes

y = 2 × 7 - 6

y = 14 - 6

y = 8

For more information about quadratic equations, visit brainly.com/question/1214333

#SPJ9

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2. A bank representative studies compound interest, so she can better serve
Kaylis [27]

Answer:

Step-by-step explanation:

Given that a  bank representative studies compound interest, so she can better serve  customers. She analyzes what happens when $2,000 earns interest several  different ways at a rate of 2% for 3 years.

a) the interest if it is computed using simple interest. 12.00

=\frac{2000(3)(12)}{100} \\=720 dollars

b) the interest if it is compounded annually.

=2000(1.12)^3-2000\\= 809.86 dollars

c) the interest if it is compounded semiannually

=2000(1.06)^6 -2000\\= 837.04

d) the interest if it is compounded quarterly.

=2000(1.03)^12 -2000\\= 851.52

e) the interest if it is compounded monthly.

=2000(1.01)^24 -2000\\= 861.54

4 0
3 years ago
Please help! I keep on getting the wrong answer!
valentina_108 [34]

Answer:

CODE: 1977.98

Step-by-step explanation:

A.

(To get the closest answer, round the circumference to the nearest ten thousandth.)

C = 2(3.14)r                      Circumference formula: C = 2πr

C = 2(3.14)(3)

C = 18.84

B.

A = (3.14)r²

A = (3.14)(3)²

A = (3.14)(9)

A ≈ 28.26

C. (It's asking for the circumference.)

C = 2(3.14)r

C = 2(3.14)(58)

C ≈ 364.24

D. (It's a linear pair, which is 180 degrees.)

4x + 2x = 180

6x = 180

x = 30

m∠ABD = 4x

m∠ABD = 4(30)

m∠ABD = 120°

E. (∠GHI & ∠JHK are vertical angles, so they are congruent.)

x + 7 = 3x - 21

28 = 2x

14 = x

F. (x = 14)

m∠JHK = 3x - 21

m∠JHK = 3(14) - 21

m∠JHK = 42 - 21

m∠JHK = 21°

G. (Supplementary - two angles that add up to 180 degrees.)

180 - 84

= 96°

CODE: E(C - D) - F(G - B) - A

CODE: 14(364.24 - 120) - 21(96 - 28.26) - 18.84

CODE: 14(244.24) - 21(67.74) - 18.84

CODE: 3419.36 - 1422.54 - 18.84

CODE: 1977.98

8 0
2 years ago
Positive and negative relationships are both examples of linear relationships
NARA [144]

Answer: A. True.

Step-by-step explanation:

A relationship is linear when the points on a scatterplot follow a somewhat straight line pattern. This is the relationship that we will examine. Linear relationships can be either positive or negative. Positive relationships have points that incline upwards to the right. As x values increase, y values increase.

4 0
2 years ago
What is 3b(8)+(-2)(7c);for b=2,c=3
BabaBlast [244]

Answer:

6

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
Rohan did a survey in four bird parks and wrote the following observations:
stiks02 [169]

Answer:  Park P

Step-by-step explanation:

Since, According to the question,

Number of yellow bird in park P = 33

Total number of the bird in park P = 53

Thus, the percentage of yellow bird in park P = \frac{33}{53} \times 100= 62.264150943% ≈ 62 %

Number of yellow bird in park Q = 20

Total number of the bird in park Q = 48

Thus, the percentage of yellow bird in park P = \frac{20}{48} \times 100=41.666666666% ≈ 42%

Number of yellow bird in park R = 54

Total number of the bird in park R = 90

Thus, the percentage of yellow bird in park R = \frac{54}{90} \times 100= 60 %

Number of yellow bird in park S = 44

Total number of the bird in park S = 83

Thus, the percentage of yellow bird in park P = \frac{44}{83} \times 100=53.012048192 % ≈ 53 %

Since, 62% > 60% > 53% > 42%

Therefore, highest percentage of the yellow bird is 62 %

Which is present in park P.

8 0
3 years ago
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