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DerKrebs [107]
1 year ago
8

Find the solution(s) of the system of equations:

Mathematics
1 answer:
murzikaleks [220]1 year ago
7 0

The solutions are (0, - 6) ,(7, 8)

The given system of equations is expressed as

y = x² - 5x - 6- - - - - - - - - - - - (1)

y = 2x - 6- - - - - - - - - - - (2)

We would apply the method of substitution by substituting equation 2 into equation 1. It becomes

x² - 5x - 6 = 2x - 6

x² - 5x - 6 = 2x - 6

x² - 5x - 2x - 6 + 6 = 0

x² - 7x = 0

x(x - 7) = 0

x = 0 or x - 7 = 0

x = 7 or x = 0

Substituting x = 0 into equation 2, it becomes

y = 2 × 0 - 6

y = - 6

Substituting x = 7 into equation 2, it becomes

y = 2 × 7 - 6

y = 14 - 6

y = 8

For more information about quadratic equations, visit brainly.com/question/1214333

#SPJ9

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Lelechka [254]

Answer:

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7 0
3 years ago
Please answer ASAP i need help please explain.
Phoenix [80]

Answer:

no

Step-by-step explanation:

3/4-2/3=9/12-8/12=1/12

4 0
3 years ago
2. Find the distance between A (-1, 4) and B (1.-1)<br> 5.39<br> 5.19<br> 5.29<br> 5.09
Verizon [17]
<h3>Answer: A) 5.39</h3>

=====================================================

Explanation:

Apply the distance formula.

d = \sqrt{ (x_1-x_2)^2+(y_1-y_2)^2}\\\\d = \sqrt{ (-1-1)^2+(4-(-1))^2}\\\\d = \sqrt{ (-1-1)^2+(4+1)^2}\\\\d = \sqrt{ (-2)^2+(5)^2}\\\\d = \sqrt{ 4+25}\\\\d = \sqrt{ 29}\\\\d \approx 5.38516\\\\d \approx 5.39\\\\

You could also use the pythagorean theorem which is what the distance formula is based off of.

6 0
3 years ago
What is the solution to this system of equations?
damaskus [11]

Since this is multiple choice ...

• check if B is correct:

x = 0, y = 4, z = 1   ⇒   3x - y + 4z = -4 + 4 = 0 ≠ -10

(it's not)

• check if C is correct:

x = -2, y = 4, z = 0

⇒   3x - y + 4z = -6 - 4 + 0 = -10

⇒   3x - y + 4z = 2 + 4 + 0 = 6

⇒   3x - y + 4z = -4 - 4 + 0 = -8

While this solution does satisfy the system, it can still have infinitely many other solutions that would work.

• check if D is correct:

Eliminate one of the variables from each equation. For instance,

(3x - y + 4z) + (-x + y + 2z) = -10 + 6

2x + 6z = -4

x + 3z = -2

and

(2x - y + z) + (-x + y + 2z) = -8 + 6

x + 3z = -2

but now it's impossible to eliminate one of the variables.

Therefore there are infinitely many solutions to the system [D].

3 0
1 year ago
Add 3x to 4 <br> a. 7x<br> b. 7<br> c. 34x<br> d. 4+3x
AleksandrR [38]
D

Please mark brainliest
4 0
2 years ago
Read 2 more answers
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