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Vesnalui [34]
3 years ago
13

My 4 closet friends have weekly allowance of $13, $17, $24, $30. What are the possible values of my weekly allowance if the medi

an of our allowance equal the average of our allowance.
Mathematics
1 answer:
Nata [24]3 years ago
5 0

Answer:

The median is 20.5

the average is 21

Step-by-step explanation:

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What is 3+3 I don't """""""
iogann1982 [59]

Answer:

3+3 is 6.

Have a great day and stay safe! :) :D :3

5 0
3 years ago
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What is the solution to 2/3(9x-6)=4(x+2)+ 2 round to the nearest hundredth
ipn [44]

Answer:

7

Step-by-step explanation:

First expand 2/3 (9x-6) = 4 (x+2)+ 2 By doing 2/3 (9x - 6)/3

Which gives you 2/3 (9x - 6)

Then you factor it 2/3 (9x - 6) 6 (3x - 2) get 6 (3x - 2) / 3

then you divide 6/3 with 2

Getting 2 (3x - 2)

The use the distributive law

2 x 3x - 2 x 2

simplify the equation

6x - 4

expand 4 (x +2) + 2:   4x + 10

which then equals 6x-4=4x+10

add 4 to both sides

6x-4+4=4x+10+4

simplify

6x=4x+14

subtract 4x from both sides

simplify again

2x=14

divide both sides by 2

2x/2 = 14/2

simplify one last time and get the answer

x=7

8 0
2 years ago
point b on the ground is 5 cm from point E at the entrance to Ollie's house. He is 1.8 m tall and is standing at Point D, below
enot [183]

Point B on the ground is 5 cm from point E at the entrance to Ollie's house.

Ollie is at a distance of 2.45 m from the entrance to his house when he first activates the sensor.

The complete question is as follows:

Ollie has installed security lights on the side of his house that is activated by a  sensor. The sensor is located at point C directly above point D. The area covered by the sensor is shown by the shaded region enclosed by triangle ABC. The distance from A to B is 4.5 m, and the distance from B to C is 6m. Angle ACB is 15°.

The objective of this information is:

  • To find angle CAB and;
  • Find the distance Ollie is from the entrance to his house when he first activates the sensor.

The diagrammatic representation of the information given is shown in the image attached below.

Using  cosine rule to determine angle CAB, we have:

\mathbf{\dfrac{AB}{Sin \hat {ACB}} = \dfrac{BC}{Sin \hat {CAB}}= \dfrac{CA}{Sin \hat {ABC}}}

Here:

\mathbf{\dfrac{AB}{Sin \hat {ACB}} = \dfrac{BC}{Sin \hat {CAB}}}

\mathbf{\dfrac{4.5}{Sin \hat {15^0}} = \dfrac{6}{Sin \hat {CAB}}}

\mathbf{Sin \hat {CAB} = \dfrac{Sin 15 \times 6}{4.5}}

\mathbf{Sin \hat {CAB} = \dfrac{0.2588 \times 6}{4.5}}

\mathbf{Sin \hat {CAB} = 0.3451}

∠CAB = Sin⁻¹ (0.3451)

∠CAB = 20.19⁰

From the diagram attached;

  • assuming we have an imaginary position at the base of Ollie Standing point called point F when Ollie first activates the sensor;          

Then, we can say:

∠CBD = ∠GBF

∠GBF = (CAB + ACB)      

(because the exterior angles of a Δ is the sum of the two interior angles.

∠GBF = 15° + 20.19°

∠GBF = 35.19°

Using the trigonometric function for the tangent of an angle.

\mathbf{Tan \theta = \dfrac{GF}{BF}}

\mathbf{Tan \ 35.19  = \dfrac{1.8 \ m }{BF}}

\mathbf{BF  = \dfrac{1.8 \ m }{Tan \ 35.19}}

\mathbf{BF  = \dfrac{1.8 \ m }{0.7052}}

BF = 2.55 m

Finally, the distance of Ollie║FE║ from the entrance of his bouse is:

= 5 - 2.55 m

= 2.45 m

Therefore, we can conclude that Ollie is at a distance of 2.45 m from the entrance to his house when he first activates the sensor.

Learn more about exterior angles here:

8 0
3 years ago
What is 2 to the second power
inessss [21]
2^2 = 4
just think 2 written out TWO times (hence the SECOND power).
5 0
3 years ago
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An average swimming pool contains 19200 gallons of water. The pool needs drained at the end of the summer. Water drains from the
Sergeu [11.5K]

Answer:

The answer is

D. V= 19200- 12t

Step-by-step explanation:

in this problem, we already know that the pool contains 19200 gallons of water

and the pool is draining at 12 gallons per minutes, hence the volume is decreasing at that rate

Therefore for t minutes it will decrease by 12t

hence the volume after t minutes will be

V= 19200-12t

7 0
3 years ago
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