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Thepotemich [5.8K]
1 year ago
5

Squared root 50 x squared root 8 surds

Mathematics
1 answer:
frez [133]1 year ago
6 0

Answer:

20

Step-by-step explanation:

using the rule of radicals

\sqrt{a} × \sqrt{b} = \sqrt{ab} , then

\sqrt{50} × \sqrt{8}

= \sqrt{50(8)}

= \sqrt{400}

= 20

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Can someone help me with this question on Prodigy? ​
lions [1.4K]

Answer:

  8 +(3/8)√53 in² ≈ 10.73 in²

Step-by-step explanation:

Given the net of a triangular pyramid with some of the dimensions filled in, you want to find the total surface area.

<h3>Triangle base</h3>

The triangle bases identified by dashed lines will have a length equal to the hypotenuse of the right triangles with legs shown as solid lines. The legs of each of those right triangles are ...

  a = (3 in)/2 = 1.5 in

  b = 2 in . . . . . . shown as the altitude of the triangle

Then the hypotenuse is found using the Pythagorean theorem:

  c² = a² +b²

  c² = 1.5² +2² = 2.25 +4 = 6.25

  c = √6.25 = 2.5

The dashed lines are 2.5 inches long.

<h3>Triangle altitude</h3>

The altitude from the solid horizontal line to the vertex at the bottom of the figure can be found using the fact that all of the outside edge lengths of the net are the same length. That edge length is found as the length of the hypotenuse of the right triangles in the left- and right-sides of the upper portion of the net. Each of those has a leg that is (2.5 in)/2 = 1.25 in and a leg marked as 2 in.

  c² = a² +b²

  c² = 1.25² +2² = 1.5625 +4 = 5.5625

  c = (√89)/4 ≈ 2.358 . . . in

The unmarked altitude of the bottom triangle is then ...

  b² = c² -a²

  b² = 89/16 -1.5² = 53/16

  b = (√53)/4 ≈ 1.820 . . . in

<h3>Surface area</h3>

The surface area of the figure is the sum of the areas of the four triangles that make up the net. Each triangle has an area given by the formula ...

  A = 1/2bh

The left and right triangles have b=2.5, h=2, so they each have an area of ...

  A = 1/2(2.5)(2) = 2.5 . . . . in²

The center triangle has dimensions of b=3, h=2, so an area of ...

  A = 1/2(3)(2) = 3 . . . . in²

The bottom triangle has dimensions of b=3, h=(√53)/4, so an area of ...

  A = 1/2(3)(√53/4) = (3/8)√53 ≈ 2.730 . . . . in²

The total surface area is the sum of the areas of these triangles, so is ...

  A = 2.5 in² +2.5 in² +3 in² +2.73 in² = 10.73 in²

The surface area of the triangular pyramid is (64+3√53)/8 ≈ 10.73 in².

__

<em>Additional comment</em>

Often we work with pyramids that are rotationally symmetrical about a vertical line through the peak. This one is not. The altitude of the bottom triangle in the net is less than the altitude of the other triangles. This short face of the pyramid will tend to be more vertical than the other two lateral faces.

4 0
1 year ago
Draw to show how you can use model to compare 345 and 391
Oksi-84 [34.3K]
You could use graphs like hundreds graphs ;/
8 0
3 years ago
Answer with at least 3-4 sentences. No fake answers lots of points
Rus_ich [418]

Answer:

4

Step-by-step explanation:

Calculation of the discriminant of the polynomial : x⋅2−4⋅x+5

1. Applying the formula to calculate the discriminant Δ=b2−4⋅a⋅c with : a=0, b=−2,c=5

2. Δ=(−2)2−4⋅(0)⋅(5)=4=4

3. The discriminant of the polynomial x⋅2−4⋅x+5 is equal to 4

5 0
2 years ago
What number is 10% of 42
vampirchik [111]

Answer:

4.2

Step-by-step explanation:

10% of 42 is 4.2

3 0
2 years ago
Read 2 more answers
Someone please help with parts a b c and d. I will mark brainlest!!!
maria [59]

Answer:

A. 49 feet

B. 66 feet (round to the nearest foot)

C. 4 seg

Step-by-step explanation:

A. What is the height of the ball after 3 seconds?

For t=3 seg

h(3)=-16(3)^{2} +63(3)+4

h(3)=-144+189+4\\h(3)=-144+193\\h(3)=49 feet

B. What is the maximum height of the ball? round to the nearest foot

h(t)=-16(t)^{2} +63(t)+4\\h'(t)=-32(t) +63\\

then

-32(t)+63=0\\t=\frac{-63}{-32}\\t=1.969seg

For t=1.969seg

h(1.969)=-16(1.969)^{2}+63(1.969)+4\\h(1.969)= 66.016\\h(1.969)=66 feet

C. When will the ball hit the ground?

The ball will hit the ground when h(t)=0

so, -16t^{2} +63(t)+4=0

Using the quadratic equation

t=4seg

6 0
3 years ago
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