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Lemur [1.5K]
2 years ago
5

Write two equations for two perpendicular lines that have the same y intercept and do not pass through the same origin 15Points

Mathematics
1 answer:
Zanzabum2 years ago
8 0

Two equations for two perpendicular lines that have the same y-intercept and do not pass through the same origin are; y = x + 1 and y = -x + 1

<h3>What is the equation of the two lines?</h3>

The general formula for the equation of a line in slope intercept form is;

y = mx + c

where;

m is slope

c is y-intercept

Now, when we talk about two perpendicular lines, it means that their slopes are negative reciprocals of each other.

Secondly, we are told that they both do not pass through the origin. Thus, it means that the y-intercept cannot be zero.

Therefore, two possible equations here can be;

y = x + 1 and y = -x + 1

Read more about Equation of lines at; brainly.com/question/13763238

#SPJ1

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lara [203]

Answer:

a. b=2

b. b = 2a

c. a = \frac{1}{2}b\\

d. b = 10

Step-by-step explanation:

Gradient is just another similar term for slope l, m, and it can be calculated by m = \frac{y_2 -y_1}{x_2 -x_1}\\ where x_n and 1y_n is the xy-coordinates of point n

We let (0,0) be point 1 and (a,b) be point 2, we can then write the equation:

m = \frac{b -0}{a -0}\\ m = \frac{b}{a}.

It also says that the points are with a gradient of 2 so m = 2. We can then write the equation:

2 = \frac{b}{a}\\

Finding bIf a = 1:

2 = \frac{b}{a} \\ 2 = \frac{b}{1} \\ 2 = b \\ b = 2

Writing an expression for b in terms of a.

2 = \frac{b}{a} \\ \frac{b}{a} = 2 \\ \frac{b}{a} \times a = 2 \times a \\ b = 2a

Writing an expression for a in terms of b

2 = \frac{b}{a} \\ \frac{b}{a} = 2 \\ \frac{a}{b} = \frac{1}{2} \\ \frac{a}{b} \times b = \frac{1}{2} \times b \\ a = \frac{1}{2}b

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2 = \frac{b}{a} \\ 2 = \frac{b}{5} \\ \frac{b}{5} = 2 \\ \frac{b}{5} \times 5 = 2 \times 5 \\ b = 10

4 0
3 years ago
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ra1l [238]

Answer:

y < -2

Step-by-step explanation:

it cannot be anything with ≤ bc the circle is open

and y is < -2 because the arrow goes left basically selecting all of the numbers less than -2

4 0
3 years ago
A manufacturing plant earned $80 per man hour of labor when it opened. Each year, the plant earns an additional 5% per man hour.
Mekhanik [1.2K]

Answer:

The amount that plant earns per man hour after (t) years it open is           $80 (1.05)^{\textrm t} .

Step-by-step explanation:

Given as :

The earning of  manufacturing plant when it opened = $ 80 per man hour

The rate of plant earning per man hour  = 5 %

Let The earning of plant after t years = A( t )

So,

The earning of plant after t years = initial earning × (1+ \dfrac{\textrm rate}{100})^{\textrm Time}

Or, A(t) = $ 80 × (1+ \dfrac{\textrm 5}{100})^{\textrm t}

or, A(t) = $ 80 × (1.05)^{\textrm t}

Hence The amount that plant earns per man hour after (t) years it open is   $80 (1.05)^{\textrm t} . Answer

3 0
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Answer:

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