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dimaraw [331]
3 years ago
6

A rock weighs 80 g on a triple beam scale. The same rock is then gently placed inside a graduated cylinder containing 30 mL of w

ater. If the water level in the graduated cylinder rises to 75 mL. What is the density of the rock
Mathematics
1 answer:
Alexxandr [17]3 years ago
3 0

Answer:

  • 1.78 g/cm³

Step-by-step explanation:

<u>80 g rock displaces water:</u>

  • 75 ml - 30 ml = 45 ml = 45 cm³

<u>Density = mass / volume:</u>

  • d = 80 g / 45 cm³
  • d = 1.78 g/cm³ (rounded)
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The 12 ounce can, because it only costs $.58 for 36 ounces, which means each ounce costs $.016, whereas the 14.5 ounce cans cost $1.00 for 58 ounces, which means each ounce costs $.017.

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3 years ago
The <img src="https://tex.z-dn.net/?f=%5Csqrt%7B32%7D" id="TexFormula1" title="\sqrt{32}" alt="\sqrt{32}" align="absmiddle" clas
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5 and 6

Step-by-step explanation:

The square root of 32 is between two integers which are 5 and 6.

     5 < \sqrt[2]{32} < 6

Integers are sets of numbers that are made up of whole numbers;

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learn more:

Square root problems brainly.com/question/4034547

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4 years ago
Jamie bought 10 packs of red bouncy balls and 8 packs of yellow bouncy balls. Each package
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Step-by-step explanation:

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4 years ago
There are three boxes: one with two golden coins, one with two silver coins, and one with one golden coin and one silver coin. A
krek1111 [17]

Answer:

Step-by-step explanation:

From Bayes' theorem is stated mathematically as the following equation:[2]

{\displaystyle P(A\mid B)={\frac {P(B\mid A)\,P(A)}{P(B)}},}

where A and B are events and P(B) ≠ 0.

P(A) and P(B) are the probabilities of observing A and B without regard to each other.

P(A | B), a conditional probability, is the probability of observing event A given that B is true.

P(B | A) is the probability of observing event B given that A is true.

At this point, go through the attached file before you continue with part B.

Part B)

P(silver) = P(silver from SS)+P(silver from GS)

note P(SS)=P(GG)=P(GS) = 1/3

P(silver from SS) = 1

P(silver from GS) = 1/2

hence

P(Silver from SS) = 1/3

P(Silver from GS) = 1/3 *1/2

P(Silver) = 1/3*1+1/3*1/2

required probability = P(Silver from SS)/P(Silver) = 2/3

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3 years ago
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