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1 year ago

Find the measure of ZB.

1 answer:

6 0

The sum of the inside angles of a triangle, always sum up to 180 degrees. Using this information, we can create the following equation for this problem:

$(3x-2)\text{ +(6}x\text{+11)+(5}x\text{ +3) = 180}$

Adding up all terms with 'x' and adding the other together, we have the following equation:

$\begin{gathered} (3x+6x+5x)+(11+3-2)=180_{} \\ 14x+12=180 \\ 14x=180-12=168 \end{gathered}$

Solving this last equation for 'x', we have the following:

$\begin{gathered} 14x=168 \\ x=\frac{168}{14}=12 \end{gathered}$

Then, the final answer for the 'x' value is twelve!

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If n = 8 and 16 • 2m = 4n – 8, then m = ?

max2010maxim [7]

Answer:

m = 0.75

Step-by-step explanation:

16 x 2m = 4x8 - 8

32m = 24

m = 24/32

5 0

3 years ago

What is the definition of csc θ ?

Greeley [361]

Csc is the inverse of sin. This means the formula in regards to a triangle for csc is h/o, unlike o/h for sin. csc can also be knows as 1/sin.

3 0

4 years ago

Use function g, shown in the graph below.

Katyanochek1 [597]

You should search it up on Photomath is easier

5 0

4 years ago

Read 2 more answers

Sam has 1000 to distributed among two groups equally. Later ,the first part is divided among five children and second part is di

melisa1 [442]

So basically sam split the 1000 to 2 groups so we have 1000 ÷ 2
now the first group divided the 500 (since 1000÷ 2 is 500) among five children so it would be 500 ÷ 5 which equals 100 per child and the second group divided their 500 between to boys, so you would get 500÷2 which is 250
so for group one it would be: 1000÷2÷5 which equals 100 per child and the second group is 1000÷2÷2 which equals 250 for each brother

3 0

3 years ago

I only need help on the second and third one

Iteru [2.4K]

let's first off notice that, on the 2), the sector is really half of the whole circle, and on 3) the sector is one quarter of the whole circle.

now, on 2) AB is the diameter of 4 units, therefore it has a radius of 2, or half that.

$\bf \boxed{2} \\\\\\ \stackrel{\textit{area of a circle}}{A=\pi r^2}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=2 \end{cases}\implies A=\pi 2^2\implies A=4\pi \\\\\\ \stackrel{\textit{half of that}}{A=2\pi}\implies A=\stackrel{\textit{rounded up}}{A=6.3~ft^2} \\\\[-0.35em] ~\dotfill$

$\bf \boxed{3} \\\\\\ \stackrel{\textit{area of a circle}}{A=\pi r^2}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=20 \end{cases}\implies A=\pi 20^2\implies A=400\pi \\\\\\ \stackrel{\textit{one quarter of that}}{A=100\pi }\implies \stackrel{\textit{rounded up}}{A=314.2~in^2}$

8 0

3 years ago