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WINSTONCH [101]
3 years ago
10

What is the standard form of the equation of the line through (6,-3) with a slope of 2/3

Mathematics
2 answers:
sasho [114]3 years ago
7 0
Y-y1 = m(x-x1)
y+3 = 2/3(x-6)
y+3 = 2/3 x -4
y = 2/3 x -7
mult both sides by 3 to get rid of the fraction so. 3y=2x - 7

then put in proper order

2x - 3y = 7
tangare [24]3 years ago
5 0
Ax+by=c is the standard form
you are given the slope and a point, so first write the equation in point-slope form:
y-(-3)=2/3(x-6)
expand the equation: y+3=(2/3)x-4
(2/3)x-y=7 is the standard form
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3 0
3 years ago
Melissa is 29 meters below the surface. After swimming 12 minutes she rises upward 15 meters. What is her final depth?
pav-90 [236]

Answer:

The final depth of Melissa is 14 meters below the surface

Step-by-step explanation:

In this kind of problems, involving directions, etc, usually one position is the positive direction and the other position is the negative direction.

In our problem, we suppose that the surface is the positivo zero, above the surface is the positive position(positive depth) and below the surface is the negative directions(negative depth).

The problem states that Melissa is 29 meters below the surface. So, her initial position is 29 meters in the negative direction, so it is equal to -29.

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<h2>John has $15 and Alex has $33</h2>

Step-by-step explanation:

a systems of equations can be made from the information on the problem

x+y=48

x=2y+3

since x= 2y+3 substitute 2y+3 in the firat equation to get:

(2y+3)+y=48  -> 3y+3=48 -> 3y=45  -> y=15

plug in 15 for y in the second equation to solve for x

x+15 =48 --> x=33

8 0
2 years ago
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